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NemiM [27]
3 years ago
11

The picture below shows the position of Earth and two stars.

Physics
2 answers:
alexgriva [62]3 years ago
8 0

The answer is:

18 years.

The explanation:

when Star 1 is 34 light years from Earth and Star 2 is 52 light years from Earth. that means the distance between star 1 and star 2 is 52-34 = 18 years so, If Star 2 explodes as a supernova so,  the explosion would take 18 years to be seen from a planet orbiting Star 1.


abruzzese [7]3 years ago
3 0
The picture below shows the position of Earth and two stars.Star 1 is 34 light years from Earth and Star 2 is 52 light years from Earth. If Star 2 explodes as a supernova, I believe that A. 18 light years would pass before the explosion is seen from a planet orbiting Star 1.
But I am not sure, sorry. :/
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The concept required to solve this problem is hydrostatic pressure. From the theory and assuming that the density of water on that planet is equal to that of the earth (1000kg / m ^ 3)we can mathematically define the pressure as

P = \rho g h

Where,

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h = Height

g = Gravitational acceleration

Rearranging the equation based on gravity

g = \frac{P_h}{\rho h}

The mathematical problem gives us values such as:

P = 2.4 atm (\frac{101325Pa}{1atm}) = 243180Pa

\rho = 1000kg/m^3

h = 28.6m

Replacing we have,

g = \frac{243180}{(1000)(28.6)}

g = 8.5m/s^2

Therefore the gravitational acceleration on the planet's surface is 8.5m/s^2

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3 years ago
Two point charges, A and B, are separated by a distance of 19.0 cm . The magnitude of the charge on A is twice that of the charg
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Answer:

QA = 19μC

QB = 9.5 μC

Explanation:

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       F_{AB} = \frac{k*Q_{A} * Q_{B}}{r_{AB}^{2}}  (1)

  • We know that the value of the magnitude of FAB  is 45.0 N, the distance between QA and  QB is 0.19 m, and that QA = 2*QB.
  • Replacing in (1), we can solve for QB, as follows:

      Q_{B} = \sqrt{\frac{F_{AB}*r_{AB} ^{2}}{2*k} } = \sqrt{\frac{45.0N*(0.19m) ^{2}}{2*9e9N*m2/C2} } = 9.5e-6 C  (2)

  • Since QA = 2*QB
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2 years ago
Which are true of alpha radiation?
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3 years ago
In reaching her destination, a backpacker walks with an average velocity of 1.34 m/s, due west. This average velocity results be
Ivanshal [37]

We can define average velocity as:

av = (total distance travelled)/(total time)

Only using the above equation, we will find that she walked 807.3m due east.

<em>The given information is:</em>

The average velocity is 1.34 m/s due west.

(we can define west as the positive side and east as the negative side).

We know that first, she hikes 6.44km due west with an average velocity of 2.68 m/s.

To get the total time it took we write the equation:

2.68 m/s = (6,440m)/(time)

time = 6,440m/(2.68 m/s) = 2,402.9 seconds.

Then she hikes a distance D due east with an average velocity of 0.447 m/s, because she goes due east, we will write -D in the equations.

Now using the same equation as before, we can get the time as:

time' = -D/(-0.447 m/s) = D/(0.447 m/s)

Now the equation for the total average velocity will be:

1.34 m/s = (6,440m - D)/(2,402.9 s +  D/(0.447 m/s))

Now we need to solve this for D.

(1.34 m/s)*(2,402.9 s +  D/(0.447 m/s)) =  (6,440m - D)

(1.34 m/s)*(2,402.9 s) + (1.34 m/s)*(D/(0.447 m/s) =6,440m - D

(1.34 m/s)*(D/(0.447 m/s) + D = 6,440m - (1.34 m/s)*(2,402.9 s) = 3,229.1 m

D*(1 + (1.34m/s)/(0.447 m/s)) = 3,229.1 m

D*4 = 3,229.1 m

D =  3,229.1 m/4 = 807.3 m

We can conclude that she walked 807.3m due east.

If you want to learn more, you can read:

brainly.com/question/862972

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Answer:

A pair of oxygen atoms is a molecule of oxygen. A molecule is the smallest particle of a substance that exists independently. Molecules of most elements are made up of only one of atom of that element. Oxygen, along with nitrogen, hydrogen, and chlorine are made up of two atoms.

Explanation:

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