Ask question

Ask question

All categories

3 years ago

11

The picture below shows the position of Earth and two stars.

2 answers:

alexgriva [62]3 years ago

8 0

The answer is:

18 years.

The explanation:

when Star 1 is 34 light years from Earth and Star 2 is 52 light years from Earth. that means the distance between star 1 and star 2 is 52-34 = 18 years so, If Star 2 explodes as a supernova so, the explosion would take 18 years to be seen from a planet orbiting Star 1.

abruzzese [7]3 years ago

3 0

The picture below shows the position of Earth and two stars.Star 1 is 34 light years from Earth and Star 2 is 52 light years from Earth. If Star 2 explodes as a supernova, I believe that A. 18 light years would pass before the explosion is seen from a planet orbiting Star 1.
But I am not sure, sorry. :/

You might be interested in

An oxygen atom can absorb any frequency of light to cause its electrons to increase in energy.

sashaice [31]

Answer:

that's true.

Explanation:

that's the reason why oxygen supports burning.

8 0

1 year ago

A dog jumps 0.80 m to catch a treat. The dog's displacement vector is shown below.

Brrunno [24]

Answer:D

Explanation:

It was right o khan academy

6 0

2 years ago

A policeman is chasing a criminal across a rooftop at 10 m/s. He decides to jump to the next building which is 2 meters across f

valina [46]

Answer:

They will meet at a distance of 7.57 m

Given:

Initial velocity of policeman in the x- direction, $u_{x} = 10 m/s$

The distance between the buildings, $d_{x} = 2.0 m$

The building is lower by a height, h = 2.5 m

Solution:

Now,

When the policeman jumps from a height of 2.5 m, then his initial velocity, u was 0.

Thus

From the second eqn of motion, we can write:

$h = ut + \frac{1}{2}gt^{2}$

$h = \frac{1}{2}gt^{2}$

$2.5 = \frac{1}{2}\times 10\times t^{2}$

t = 0.707 s

Now,

When the policeman was chasing across:

$d_{x} = u_{x}t + \frac{1}{2}gt^{2}$

$d_{x} = 10\times 0.707 + \frac{1}{2}\times 10\times 0.5 = 9.57 m$

The distance they will meet at:

9.57 - 2.0 = 7.57 m

8 0

3 years ago

A bullet is fired at an angle θ above the horizontal with an initial velocity of 800 m/s from the top of an 80 m high tower. Wha

Irina-Kira [14]

Answer:

pahingi po ng pic pls para masagutang kopo iyan

6 0

2 years ago

5.0 kg, with a bullet of mass 0.1 kg. The target was mounted on

kari74 [83]

Answer:

306 m/s

Explanation:

Law of conservation of momentum

m1v1 + m2v2 = (m1+m2)vf

m1 is the bullet's mass so it is 0.1 kg

v1 is what we're trying to solve

m2 is the target's mass so it is 5.0 kg

v2 is the targets velocity, and since it was stationary, its velocity is zero

vf is the velocity after the target is struck by the bullet, so it is 6.0 m/s

plugging in, we get

(0.1 kg)(v1) + (5.0 kg)(0 m/s) = (0.1 kg + 5.0 kg)(6.0 m/s)

(0.1)(v1) + 0 = 30.6

(0.1)(v1) = 30.6

v1 = 306 m/s

8 0

3 years ago