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lana66690 [7]
3 years ago
15

PLEASE HELP! Describe how you could use a negatively charged Van de Graaff generator to induce a positive charge on a previously

neutral metal sphere. You may use additional materials.
Physics
1 answer:
Gnesinka [82]3 years ago
3 0

Answer:

Van de Graaff inventó el generador que lleva su nombre en 1931, con el propósito de producir una diferencia de potencial muy alta (del orden de 20 millones de volts) para acelerar partículas cargadas que se hacían chocar contra blancos fijos. Los resultados de las colisiones nos informan de las características de los núcleos del material que constituye el blanco.

El generador de Van de Graaff es un generador de corriente constante, mientas que la batería es un generador de voltaje constante, lo que cambia es la intensidad dependiendo que los aparatos que se conectan.

El generador de Van de Graaff es muy simple, consta de un motor, dos poleas, una correa o cinta, dos peines o terminales hechos de finos hilos de cobre y una esfera hueca donde se acumula la carga transportada por la cinta.

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Use the formula F = (9x10^9 Q * q) / r^2
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4 0
4 years ago
A parallel-plate vacuum capacitor has 8.60 J of energy stored in it. The separation between the plates is 3.80 mm . If the separ
creativ13 [48]

Answer:

Part a)

E = \frac{8.60}{2.62} = 3.28 J

Part b)

E = 2.62(8.60) = 22.5 J

Explanation:

As we know that the energy of capacitor when it is not connected to potential source is given as

U = \frac{Q^2}{2C}

As we know that initial energy is given as

8.60 = \frac{Q^2}{2C}

now we know that capacitance of parallel plate capacitor is given as

C = \frac{\epsilon_0A}{d}

now the new capacitance when distance is changed from 3.80 mm to 1.45 mm

C' = \frac{Cd}{d'}

C' = \frac{C(3.80)}{1.45}

C' = 2.62 C

Now the new energy of the capacitor is given as

E = \frac{Q^2}{2(2.62C)}

E = \frac{8.60}{2.62} = 3.28 J

Part b)

Now if the voltage difference between the plates of capacitor is given constant

now the energy energy of capacitor is

U = \frac{1}{2}CV^2

8.60 = \frac{1}{2}CV^2

now when capacitance is changed to new value then new energy is given as

E = \frac{1}{2}C'V^2

E = \frac{1}{2}(2.62C)V^2

E = 2.62(8.60) = 22.5 J

6 0
3 years ago
What were the patterns that people saw in the sky long ago?
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Long time ago, people saw the constellations as patterns in the sky.  They names these patterns and tell stories about them. What people saw laong time ago are just mere patterns which forms animals and shapes.  We got the names of our constellations from the Greeks who named the constellations after the mythological heroes and mythological legends.
7 0
3 years ago
Read 2 more answers
motorcycle accelerates from rest to a final velocity of 27 m/s in 9 seconds. What is its acceleration?
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Answer:

3 m/s squared

Explanation:

The formula you use is Vf= Vi + at. You rearrange it to a= Vf - Vi/t. The Vf is 27m/s. The Vi is 0m/s and the t is 9s. Cross out Vi since it’s zero and you’re left with a= 27m/s divided by 9s, which equals 3

5 0
3 years ago
What can be inferred when an atom is electrically charged?
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When an atom becomes electrically charged the number of electrons or protons stops and they are not equal again. The "extra" electron or proton is not balanced by something inside the atom any longer and it starts attracting itself to othet protons or electrons in other atoms.

<h3>What is atomic structure?</h3>

An atomic structure comprises of positively charged nucleus which is surrounded by negatively charged particles called electron and neutron which is neutral charged.

Unlike charges attract each other while like charges repel each other.

Therefore, When an electron is fully charged, the number of electrons will stop to be unequal again.

Learn more about Atomic charge here.

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7 0
2 years ago
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