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lana66690 [7]
3 years ago
15

PLEASE HELP! Describe how you could use a negatively charged Van de Graaff generator to induce a positive charge on a previously

neutral metal sphere. You may use additional materials.
Physics
1 answer:
Gnesinka [82]3 years ago
3 0

Answer:

Van de Graaff inventó el generador que lleva su nombre en 1931, con el propósito de producir una diferencia de potencial muy alta (del orden de 20 millones de volts) para acelerar partículas cargadas que se hacían chocar contra blancos fijos. Los resultados de las colisiones nos informan de las características de los núcleos del material que constituye el blanco.

El generador de Van de Graaff es un generador de corriente constante, mientas que la batería es un generador de voltaje constante, lo que cambia es la intensidad dependiendo que los aparatos que se conectan.

El generador de Van de Graaff es muy simple, consta de un motor, dos poleas, una correa o cinta, dos peines o terminales hechos de finos hilos de cobre y una esfera hueca donde se acumula la carga transportada por la cinta.

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A) Charge q1 = +5.60 nC is on the x-axis at x = 0 and an unknown charge q2 is on the x-axis at x = -4.00 cm. The total electric
jeka94

Answer:

a) F₃₁ = 63.0 μN  

b) F₃₂ = - 14.0 μN

c) q₂ = - 5.0 nC

Explanation:

a)

  • Assuming that the three charges can be taken as point charges, the forces between them must obey Coulomb's Law, and can be found independent each other, applying the superposition principle.
  • So, we can find the force that q₁ exerts along the x-axis on q₃, as follows:

       F_{31} =\frac{k*q_{1}*q_{3} }{r_{13}^{2}} = \frac{9e9Nm2/C2*5.6e-9C*2.0e-9C}{(0.04m)^{2}}  = 63.0 \mu N   (1)

b)

  • Since total force exerted by q₁ and q₂ on q₃ is 49.0 μN, we can find the force exerted only by q₂ (which is along the x-axis only too) just by difference, as follows:

      F_{32} = F_{3} - F_{31}  = 49.0\mu N  - 63.0\mu N = -14.0 \mu N  (2)

c)

  • Finally, in order to find the value of q₂, as we know the value and sign of F₃₂, we can apply again the Coulomb's Law, solving for q₂, as follows:

      q_{2}  = \frac{F_{32} * r_{23}^{2} }{k*q_{3}} = \frac{(-14\mu N)*(0.08m)^{2}}{9e9Nm2/C2* 2 nC} = - 5 nC  (3)

6 0
3 years ago
Match the type of heat transfer with its description
VikaD [51]

Answer:

1. Convection

2. Radiation

3. Conduction

Hope this helps!

Explanation:

5 0
3 years ago
a concrete slab 20 m long and weighing 400,000 N is supported by one pillar. A 19,600 N car is parked 8 meters from one end, whe
Elden [556K]

let the distance of pillar is "r" from one end of the slab

So here net torque must be balance with respect to pillar to be in balanced state

So here we will have

Mg(r - L/2) = mg(L/2 - 8)

here we know that

mg = 19600 N

Mg = 400,000 N

L = 20 m

from above equation we have

400,000(r - 10) = 19,600 (10 - 8)

r - 10 = 0.098

r = 10.098 m

so pillar is at distance 10.098 m from one end of the slab

3 0
3 years ago
Chinese public buildings erected under a construction code of the Sung dynasty have withstood earthquakes well because the white
luda_lava [24]

Answer:

A: used has four times the tensile strength of steel and the timber frame, incorporating

Explanation:

Option A is correct because it conveys the correct message intended by the statement and has no grammatical errors.

Option B is wrong because to say "has four times the tensile strength of steel has" is just grammatically and idiomatically wrong as has is used twice in the sentence.  

Option C is wrong because the statement that has to do with the flexibility of the timber's frame is more like a separate fact and does not fall under the scope of trying to further explain a fact.

Option D is wrong because it has the same problem in Option C. The comma that is placed after "steel" breaks the sentence and hence does not provide a good understanding of why the building can withstand earthquakes.

Option E is grammatically wrong for using does in the sentence "has four times the tensile strength steel does"

8 0
3 years ago
Which runner has greater kinetic energy: a 45 kg runner moving at a speed of 7 m per second or a 93 kg runner moving at a
bagirrra123 [75]

Kinetic Energy = (1/2) (mass) (speed)

First runner:  KE = (1/2) (45kg) (49 m/s)  =  1,102.5 Joules  

Second runner:  KE = (1/2) (93kg) (9 m/s)  =  418.5 Joules

The <em>first runner </em><em>has 163</em>% more kinetic energy than the second runner has.

7 0
3 years ago
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