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Simora [160]
2 years ago
6

A bicyclist starts at rest and speeds up to 30 m/s while accelerating at 4 m/s^2. Determine the distance traveled.

Physics
1 answer:
raketka [301]2 years ago
6 0

Answer:

Distance, d = 112.5 meters

Explanation:

Initially, the bicyclist is at rest, u = 0

Final speed of the bicyclist, v = 30 m/s

Acceleration of the bicycle, a=4\ m/s^2

Let s is the distance travelled by the bicyclist. The third equation of motion is given as :

v^2-u^2=2as

s=\dfrac{v^2-u^2}{2a}

s=\dfrac{(30)^2}{2\times 4}

s = 112.5 meters

So, the distance travelled by the bicyclist is 112.5 meters. Hence, this is the required solution.

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3 years ago
The magnetic force on a straight wire 0.69 m long is 1.5 x 10-3 N. The current in the wire is 16.9 A. What is the magnitude of t
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Answer:

Magnitude of magnetic field is 1.29 x 10⁻⁴ T

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Given :

Current flowing through the wire, I = 16.9 A

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Magnetic force experienced by the wire, F = 1.5 x 10⁻³ N

Consider B be the applied magnetic field.

The relation to determine the magnetic force experienced by current carrying wire is:

F = ILBsinθ

Here θ is the angle between magnetic field and current carrying wire.

According to the problem, the magnetic field and current carrying wire are perpendicular to each other, that means θ = 90⁰. So, the above equation becomes:

F = ILB

B=\frac{F}{IL}

Substitute the suitable values in the above equation.

B=\frac{1.5\times10^{-3} }{16.9\times0.69}

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7 0
3 years ago
A bridge to be fabricated of steel girders is designed to be 500 m long and 12 m wide at ambient temperature (assumed 20°C). Exp
andrew-mc [135]

Answer:

23

21.7391304348 m

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L = Initial length = 500 m

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\alpha = Coefficient of thermal expansion = 12\times 10^{-6}\ /^{\circ}C

Change in length is given by

\Delta L=L\alpha \Delta T\\\Rightarrow \Delta L=500\times 12\times 10^{-6}\times (40-(-35))\\\Rightarrow \Delta L=0.45\ m

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The length of each bridge section would be 21.7391304348 m

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