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3 years ago

A bicyclist starts at rest and speeds up to 30 m/s while accelerating at 4 m/s^2. Determine the distance traveled.

Physics

1 answer:

raketka [301]3 years ago

6 0

Answer:

Distance, d = 112.5 meters

Explanation:

Initially, the bicyclist is at rest, u = 0

Final speed of the bicyclist, v = 30 m/s

Acceleration of the bicycle, $a=4\ m/s^2$

Let s is the distance travelled by the bicyclist. The third equation of motion is given as :

$v^2-u^2=2as$

$s=\dfrac{v^2-u^2}{2a}$

$s=\dfrac{(30)^2}{2\times 4}$

s = 112.5 meters

So, the distance travelled by the bicyclist is 112.5 meters. Hence, this is the required solution.

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Hail comes straight down at a mass rate of m/Δt = 0.050 kg/s and an initial velocity of v0 = -15 m/s and strikes the roof perpen

cupoosta [38]

Answer:

$F = 1.5 N$

Explanation:

Let the hails are coming down with speed "v" and then rebound with the same speed in opposite direction

So here the change in the momentum of the hails is given as

$\Delta P = mv - (-mv)$

$\Delta P = 2mv$

now we know by Newton's 2nd Law

$F = \frac{\Delta P}{\Delta t}$

here we have

$F = \frac{\Delta m}{\Delta t} (2v)$

now plug in all data

$F = 0.050(2\times 15)$

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6 0

3 years ago

A wire with radius 23 cm has a current of 7 A which is distributed uniformly through its cross sectional area. If you were to us

Rina8888 [55]

Answer:

The magnetic induction of the magnetic field is 0.0005293 mT

Explanation:

Data given

I = 7 A = the total current in the wire

r = 23 cm = the radius of the wire = 0.23 meter

r' = 2cm = the measurement point, which should be inside the wire = 0.02 meter

Let's consider the current density is constant in the wire, ⇒ the current enclosed is a function of the enclosed area

I(enclosed) = Jπ r ²

we can consider the current density as the total current over the whole area:

I(enclosed) = I / (πr ²) * πr' ²

I(enclosed) = (I* r'²)/ (r ²)

with I = total current in the wire = 7A

With r = the radius of wire = 0.23 meter

with r' = the distance of point from the center of wire 0.02 meter

We plug this into ampere's law:

∮ *B *dl =μ 0 * (I* r'²)/ (r ²)

with B = Magnetic flux density (in Tesla) or magnetic induction

with dl = an infinitesimal element (a differential) of the curve C

with µ0 = the magnectic constant = 4π*10^−7 H/m

We can simplify this, by using an Amperian loop can write this as:

B *( 2 π r') = μ 0 * (I* r'²)/ (r ²)

Because the circumference of a circle is 2 π r , when we integrate over length at a distance r ′ from the center of wire whose crossection is a circle we get 2 π r ′

When we isolate B, we get:

B = µo *(Ir'/2 π r ²)

B = 4π*10^−7 * ((7*0.02)/2*π*0.23²)

B =5.293 *10 ^-7 T = 0.0005293 mT

The magnetic induction of the magnetic field is 0.0005293 mT

6 0

3 years ago

Which is a disadvantage of using wind as an energy source?

lesantik [10]

Answer:

it produces

Explanation:

a lot of waste

5 0

3 years ago

Read 2 more answers

A commuter airplane starts from an airport and takes theroute. The plane first flies to city A, located 175 km away in a directi

bearhunter [10]

Answer:

245.45km in a direction 21.45° west of north from city A

Explanation:

Let's place the origin of a coordinate system at city A.

The final position of the airplane is given by:

rf = ra + rb + rc where ra, rb and rc are the vectors of the relative displacements the airplane has made. If we separate this equation into its x and y coordinates:

rfX = raX+ rbX + rcX = 175*cos(30)-150*sin(20)-190 = -89.75km

rfY = raY + rbY + rcT = 175*sin(30)+150*cos(20) = 228.45km

The module of this position is:

$rf = \sqrt{rfX^2+rfY^2} = 245.45km$

And the angle measure from the y-axis is:

$\alpha =atan(rfX/rfY) = 21.45\°$

So the answer is 245.45km in a direction 21.45° west of north from city A

6 0

3 years ago

A ball rolls across a floor with an acceleration of 0.100 m/s2 in a direction opposite to its velocity. The ball has a velocity

Westkost [7]

Answer:

4.15 m/s

Explanation:

Its given that acceleration is 0.1 m/s² with a direction opposite to the velocity. Since, the direction of acceleration is opposite to the velocity, this gives us a hint that the velocity is decreasing and so acceleration would be negative.

i.e.

acceleration = a = - 0.1 m/s²

Distance covered = S = 6m

Velocity after covering 6 meters = Final velocity = $v_{f}$ = 4 m/s