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3 years ago

What does control group mean

1 answer:

7 0

A control group is the group in an experiment that does not receive any sort of change, to then be compared to the other treated objects at the end of the study.

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Which statement best describes the formula equation cl1(g) + 2kbr(aq) —> 2kcl(aq)+br2(i)

Zigmanuir [339]

Answer:

The chlorine gas and potassium bromide solution react to form liquid bromine and potassium chloride solution.

Explanation:

Chemical equation:

Cl₂(g) + KBr (aq) → KCl (aq) + Br₂(l)

Balanced chemical equation:

Cl₂(g) + 2KBr (aq) → 2KCl (aq) + Br₂(l)

This equation showed that the chlorine gas and potassium bromide solution react to form liquid bromine and potassium chloride solution.

Chlorine is more reactive than bromine it displace the bromine from potassium and form potassium chloride solution.

The given equation is balanced and completely hold the law of conservation of mass.

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

Explanation:

This law was given by french chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

8 0

3 years ago

Calcium carbide reacts with water to produce acetylene gas according to the following equation: CaC2(s) + 2H2O(l)C2H2(g) + Ca(OH

poizon [28]

Answer:

33.7

Explanation:

i just know i had a question on it'

7 0

3 years ago

A student balances the following redox reaction using half-reactions.

ICE Princess25 [194]

Answer: 6.

Explanation:

1) Aluminum

$Al^0-3e^----\ \textgreater \ Al^{3+}$

So each atom of aluminum lost 3 electrons to pass from 0 oxidation state to 3+ oxidation state.

2) Manganesium

$Mn^{2+}+2e^{-}---\ \textgreater \ Mn$

So, each ion of Mn(2+) gained 2 electrons pass from 2+ oxidation state to 0.

3) Balance

Multiply aluminum half-reaction (oxidation) by 2 and multiply manganesium half-raction (reduction) by 3:

$2Al^{0}-6e^{-}---\ \textgreater \ 2Al^{3+}

3Mn^{2+}+6e^{-}---\ \textgreater \ 3Mn^{0}$

4) Net equation

Add the two half-equations:

$2Al^{0}+3Mn^{2+}----\ \textgreater \ 2Al^{3+}+3Mn^{0}$

As you see the left side has 2 Al, 3Mn, and 3*2 positive charges.

The right side has 2 Al, 3 Mn, and 2*3 positive charges.

So, the equation is balanced.

5) Count the number of electrons involved.

As you see 2 atoms of aluminum lost 6 electrons (3 each).

That is the answer to the question. 6 electrons will be lost.

5 0

3 years ago

Read 2 more answers

The reaction of Pb+4 and O-2 produces the compound of

vovikov84 [41]

Answer:

Pb₂O₄

Explanation:

The given species are:

Pb⁴⁺ O²⁻

Now, to solve this problem, we use the combining powers which corresponds to the number of electrons usually lost or gained or shared by atoms during the course of a chemical combination.

Pb⁴⁺ O²⁻

Combining power 4 2

Exchange of valencies 2 4

Now the molecular formula is Pb₂O₄

4 0

3 years ago

PLEASE HELP MEEE!!!!

Assoli18 [71]

It would be 35.8 Calories or calories. Not sure about that part. Hope this helps though.

3 0

3 years ago