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Finger [1]
2 years ago
13

2) If 100.0 J of heat are added to 20.0 g of water at 30.0°C, what will be the final

Chemistry
1 answer:
anzhelika [568]2 years ago
3 0
The final temperature of the water will be 31.2 °C... i don’t know the second one sorry :(
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Question 6 (4 points)
pishuonlain [190]

Answer:

20.9%

Explanation:

I took the test i hope this helps:)

8 0
2 years ago
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1 C8H10(l) +21/2O2(g) → 8CO2(g) + 5H2O(g), Hcomb= ? Hf for C8H10(l) = +49.0kJ/mol C8H10(l) Use the balanced combustion reaction
nikklg [1K]

Answer:

H_{comb}=-4406kJ/mol

Explanation:

Hello,

In this case, the enthalpy of combustion is understood as the energy released when one mole of fuel, in this case octene, is burned in the presence of oxygen and is computed with the enthalpies of formation of the fuel, carbon dioxide and water as shown below (oxygen is circumvented as it is a pure element):

H_{comb}=8*\Delta _fH_{CO_2}+5\Delta _fH_{H_2O}-\Delta _fH_{C_8H_{10}}

Thus, since we already know the enthalpy of combustion of the fuel, for carbon and water we have -393.5 and -241.8 kJ/mol respectively, thereby, the enthalpy of combustion turns out:

H_{comb}=8*(-393.5kJ/mol)+5(-241.8kJ/mol)-49.0kJ/mol\\\\H_{comb}=-4406kJ/mol

Best regards.

4 0
3 years ago
Does anyone know how to do this
marshall27 [118]

Answer:

Explanation:

1-butanol has 4 carbon atoms with an OH group at the first carbon atom.

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8 0
3 years ago
In a strong acid–strong base titration (both monoprotic), if 25.0 milliliters of the base is required to completely neutralize 2
taurus [48]
B)The concentration of the acid (C₁) is the same as that of the base (C₂).

V₁=V₂

n(acid)=C₁V₁
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n(acid)=n(base)

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5 0
3 years ago
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liberstina [14]

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