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pishuonlain [190]
3 years ago
13

When using evaporation/boiling, it is

Chemistry
1 answer:
densk [106]3 years ago
3 0
The answer would be b) GAS
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C12H22O11 + 11 H2SO4 12 C + 11 H2SO4 + 11 H2O
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B: The sulfuric acid is not consumed or react with the reactant.

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Calculate the amount of HCl in grams required to react with 3.75 g of CaCO3 according to the following reaction: CaCO3(s) + 2 HC
wolverine [178]

Answer:

The correct answer is 2.75 grams of HCl.

Explanation:

The given balanced equation is:  

CaCO₃ (s) + 2HCl (aq) ⇒ CaCl₂ (aq) + H₂O (l) + CO₂ (g)

Based on the given information, one mole of calcium carbonate is reacting with two moles of HCl. The molecular mass of HCl is 36.5 grams, thus, the mass of 2 moles of HCl will be, 36.5 × 2 = 73 grams

The molecular mass of CaCO₃ is 100 gram per mole, that is, the mass of 1 mole of CaCO₃ is 100 grams, therefore, the mass of HCl required for reacting with 3.75 grams of CaCO₃ will be,  

= 3.75 × 2 × 36.5 / 100 = 2.74 grams of HCl.  

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The sugars can be classified as either aldoses or ketoses.<br><br> a. True<br> b. Fasle
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According to the Law of Conservation of Mass, the total
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Answer:

Always equal to the total moles of the products.

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