According to the balanced equation of this reaction:
N2(g) + 3H2(g) ↔ 2NH3(g)
and when we have Kp = 4.51 x 10^-5 so, in the Kp equation we will substitute by the value of the P for each gas to compare the value with Kp = 4.51x10^-5
a) when we have 98 atm NH3, 45 atm N2, 55 atm H2 by substitution in Kp equation:
Kp= [p(NH3)]^2 / [p(N2)]*[p(H2)]^3 = [98]^2 / [45]*[55]^3
= 1.28x10^-3
So here the value is higher than the value of the given Kp.
so the reaction will go leftwards toward the reactants ( to reduce the value of Kp) to reach the equilibrium.
b) When 57 atm NH3, 143 atm N2, No H2 so like a) by substitution:
Kp = [57]^2 / [143] = 22.7
So the reaction will go leftwards toward the reactants to reduce the value of Kp to reach equilibrium.
c) when 13 atm NH3, 27 atm N2, 82 H2
Kp = [13]^2 / [27]*[82]^3 = 1.135 x 10^-5 So this value is lower than the Kp which is given.
so, the reaction will go towards the right toward the products to increase the value of Kp to reach the equilibrium.
The energy needed to raise the temperature of 2.83 kg of the oil from 23 to 191 is calculated using Mc delta T formula
M= mass ( 2.83 Kg to grams = 2.83 x1000= 2830 grams)
C= specific heat capacity = 1.75 j/g/c
delta T= change in temperature = 191- 23 = 168 c
heat energy = 1.75 j/g/c x 2830 g x 168 c= 832020 J
Answer:
I will give you 5
Explanation:
color chage, formation of a precipitate, formation of a gas, odor change, temperature change. are all signs of a chemical reaction
The answer is A)radio waves, micro waves, visible light, x-rays
Density of liquid= 
.
so, density of liquid= 
= 1.2 gm/cm³.
