Answer:
-1.37 kJ/mol
Explanation:
The expression for the calculation of the enthalpy of dissolution of [tex[NH_4NO_3[/tex] is shown below as:-
Where,
is the enthalpy of dissolution of [tex[NH_4NO_3[/tex]
m is the mass
C is the specific heat capacity
is the temperature change
Thus, given that:-
Mass of ammonium nitrate = 5.60 g
Specific heat = 4.18 J/g°C
So,
Negative sign signifies loss of heat.
Also, 1 J = 0.001 kJ
So,

Also,
Molar mass of [tex[NH_4NO_3[/tex] = 80.043 g/mol
The formula for the calculation of moles is shown below:
Thus,

Thus, 
moles NaOH = c · V = 0.2753 mmol/mL · 43.44 mL = 11.959032 mmol
moles H2SO4 = 11.959032 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 5.979516 mmol
Hence
[H2SO4]= n/V = 5.979516 mmol / 54.69 mL = 0.1093 M
The answer to this question is [H2SO4] = 0.1093 M
Answer:
a. Put a piece of fresh sliced yam with a bore into it into the soup.
Explanation:
b. Osmosis may occur
Answer:
monomers
Explanation:
Thousands of molecules are called monomers