All categories

3 years ago

Convert the following:

Physics

2 answers:

Leviafan [203]3 years ago

8 0

Answers:

a. 2500000 grams

B. 1206000 seconds

c. 86400 seconds.

Look at the attached picture

Hope it will help you

Good luck on your assignment

Alika [10]3 years ago

5 0

Explanation:

A) 1 kg = 1000g

2500kg = 2500000g

B 1 hour = 3600 sec

335 hour = 1206000sec

C 1day = 24 hours

1 hour = 3600 sec

24 hours = 86400sec

You might be interested in

It is desired to create a particle of mass 7920 MeV/c^2 in a head-on collision between a proton and an antiproton (each having a

Olegator [25]

Answer:

$v=0.9714c$

Explanation:

The kinetic energy possessed by particles will be

$K.E=\frac{1}{2}Mc^2$

where,

M is the mass of the particle (7920938.3 MeV/c²)

c is the speed of the light

Also,

energy of the proton particle = $\frac{m_pc^2}{\sqrt{1-\frac{v^2}{c^2}}}$

where,

v is the velocity

m_p is the mass of the proton (938.3 MeV/c²)

since the energy is equal

thus,

$\frac{m_pc^2}{\sqrt{1-\frac{v^2}{c^2}}}=\frac{1}{2}Mc^2$

$1-\frac{v^2}{c^2}=[\frac{2m_p}{M}]^2$

substituting the values in the above equation, we get

$1-\frac{v^2}{c^2}=[\frac{2\times 938.3 }{7920}]^2$

$v=0.9714c$

Hence, the speed necessary for the specified condition to occur is 0.9714 times the speed of the light

5 0

3 years ago

Find the magnitude of the impulse delivered to a soccer ball when a player kicks it with a force of 1360 N. Assume that the play

Alona [7]

Answer:

7.59Ns

Explanation:

Given parameters:

Force = 1360N

Time of contact = 5.85 x 10⁻³s

Unknown:

Impulse = ?

Solution:

The impulse of the ball is given as:

Impulse = Force x time

Impulse = 1360 x 5.85 x 10⁻³ = 7.59Ns

4 0

3 years ago

If the strength of the magnetic field at B is 20 units, the strength of the magnetic field at A is _____.

xz_007 [3.2K]

The answer is A = 20 units

8 0

4 years ago

Read 2 more answers

A car speeds up from 13 m/s to 23 m/s in 30 seconds. What is the acceleration of the car?

ra1l [238]

Well, v = u + a×t is the equation.

v: final velocity, which is 23 m/s in this equation.
u: initialo velocity = 13 m/s 
a: acceleration = ? 
t: time = 30s

Your equation would be...

23 = 13 + a×30 
a = (23 - 13) / 30 
a = 1 / 3 
a = 0.333 m/s

7 0

3 years ago

An unstretched ideal spring hangs vertically from a fixed support. A 0.4 kg object is then attached to the lower end of the spri

musickatia [10]

Answer:

The correct answer will be "0.25 sec".

Explanation:

The graph of the given question is attached below.

According to the graph of the question,

Time,

T = 1 sec

For the upward velocity,

⇒ $t = \frac{T}{4}$

By putting the value, we get

⇒ $=\frac{1}{4}$

⇒ $=0.25 \ sec$

8 0

3 years ago