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Tomtit [17]
3 years ago
5

Convert the following:

Physics
2 answers:
Leviafan [203]3 years ago
8 0

<em>Answers</em><em>:</em>

<em>a</em><em>.</em><em> </em><em>2</em><em>5</em><em>0</em><em>0</em><em>0</em><em>0</em><em>0</em><em> </em><em>grams</em>

<em>B.</em><em> </em><em>1</em><em>2</em><em>0</em><em>6</em><em>0</em><em>0</em><em>0</em><em> </em><em>seconds</em>

<em>c</em><em>.</em><em> </em><em>8</em><em>6</em><em>4</em><em>0</em><em>0</em><em> </em><em>seconds</em><em>.</em>

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em>

<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>

Alika [10]3 years ago
5 0

Explanation:

A) 1 kg = 1000g

2500kg = 2500000g

B 1 hour = 3600 sec

335 hour = 1206000sec

C 1day = 24 hours

1 hour = 3600 sec

24 hours = 86400sec

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Kathy tests her new sports car by racing with Stan, an experienced racer. Both start from rest, but Kathy leaves the starting li
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Answer:

time at which Kathy overtakes Stan is 6.70 sec

Explanation:

given data

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acceleration= 3.4 m/s²

acceleration = 4.49  m/s²

to find out

the time at which Kathy overtakes Stan

solution

we consider here travel time for kathy = t1

and travel time for stan is = t2

and we know initial velocity = 0

so

t1 = 1 + t2

and distance travel equation by kinematic is

d1 = ut + \frac{1}{2} at²

d1 = 0+  \frac{1}{2} 4.49 (t2)²   ................1

and

d2 = 0 + \frac{1}{2} 3.4 (1+t2)²   ..................2

and when overtake distance same so  from equation 1 and 2

\frac{1}{2} 4.49 (t2)²  = \frac{1}{2} 3.4 (1+t2)²

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3 0
3 years ago
An iron bolt of mass 57.5 g hangs from a string 38.8 cm long. The top end the right from the previously vertical line f the stri
inn [45]

Answer:

tension is 0.692 N

magnetic force is 0.401 N

Explanation:

given data

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to find out

free-body diagram ,  tension and magnetic force

solution

we consider here angle is θ

so free body diagram is attach below

and

here cosθ = x/l

so θ = cos^-1 ( 0.225 / 0.388)

θ = 54.6°

so tension from net  force is

net vertical force

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t = F(g) / sinθ

t = mg /sin54.6

t = 0.0575 ( 9.8) / sin54.6

t = 0.692

so tension is 0.692 N

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net horizontal force

- t cosθ + F(magnetic) = 0   ....................2

t cosθ = F(magnetic)

put here all value

F(magnetic) = 0.692 × cos 54.6

F(magnetic) = 0.401

so magnetic force is 0.401 N

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