Answer:
B
Explanation:
The tendency of a liquid to convert to vapour increases smoothly with increasing temperature. Vapour pressure shows the tendency of a liquid to convert to vapour. Increase In vapour pressure shows an increased tendency to convert to vapour. The higher the temperature, the higher the vapour pressure.
Answer:
Average atomic mass of uranium= 237.98 amu.
Explanation:
Given data:
Abundance of U²³⁴ = 0.01%
Abundance of U²³⁵ = 0.17%
Abundance of U²³⁸ = 99.28%
Average atomic mass = ?
Solution:
Average atomic mass of uranium = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) +(abundance of 3rd isotope × its atomic mass) / 100
Average atomic mass of uranium= (234×0.01)+(235×0.71)+(238×99.28)/100
Average atomic mass of uranium= 2.34 + 166.85 + 23628.64 / 100
Average atomic mass of uranium= 23797.83 / 100
Average atomic mass of uranium= 237.98 amu.
You just have to convert the mass of water into volume.
To do that you use the density of water, which is about 1.0 g/ ml
So, from the formula of density D = M / V, you get V = M / D
=> V = 2.49 * 10^7 grams / 1.0 g / ml = 2.49 * 10 ^ 7 ml
You can pass that to liters using the conversion factor 1000 ml = 1 l
2.49 * 10^7 ml * 1 l / 1000 ml = 2.49 * 10^4 l = 24,900 l
Answer: 24,900 l
Answer:true
Explanation:
The neutrons and the protons are what stay there