Answer:
30 mL VOLUME OF 3.0 M HCl SHOULD BE USED BY THE STUDENT TO MAKE A 1.80 M IN 50 mL OF HCl.
Explanation:
M1 = 3.00 M
M2 = 1.80 M
V2 = 50 .0 mL = 50 /1000 L = 0.05 L
V1 = unknown
In solving this question, we know that number of moles of a solution is equal to the molar concentration multiplied by the volume. To compare two samples, we equate both number of moles and substitute for the required component.
So we use the equation:
M1 V1 = M2 V2
V1 = M2 V2 / M1
V2 = 1.80 * 0.05 / 3.0
V2 = 0.09 /3.0
V2 = 0.03 L or 30 mL
To prepare the sample of 1.80 M HCl in 50.0 mL from a 3.0 M HCl, 30 mL volume should be used.
Answer:
Ionul de hidroniu este un factor important atunci când avem de-a face cu reacții chimice care apar în soluții apoase. Concentrația sa în raport cu hidroxidul este o măsură directă a pH-ului unei soluții. Se poate forma atunci când un acid este prezent în apă sau pur și simplu în apă pură. Formula chimică este H3O +
Explanation:
The hydronium ion is an important factor when dealing with chemical reactions that occur in aqueous solutions. Its concentration relative to hydroxide is a direct measure of the pH of a solution. It can be formed when an acid is present in water or simply in pure water. It's chemical formula is H3O+
marke me as brainliest please
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Answer:
Explanation:
In this case the answer would be
Water is a polar molecule with positive and negative side
Now since these negative and positives are present in the water molecule . In easy terms when a substance reacts with water .the negative part of water ( oxygen ) reacts with the positive part of the substance and the positive part of the water ( hydrogen) reacts with negative part of the substance .if you look at the reason . Water is held up by one of the strongest attraction forces available .since most substances have weaker attraction forces between them ,therefore water can easily overcome them with its forces. Thus giving it the ability to dissolve a variety of substances
Answer:
C.) 2
Explanation:
The pH equation is:
pH = -log[H⁺]
In this equation, [H⁺] is the molarity of the acid. In this case, the acid is HCl. Molarity can be found using the equation:
Molarity (M) = moles / volume (L)
Since you were given moles and volume, you can find the molarity of HCl.
Molarity = moles / volume
Molarity = 0.01 moles / 1.00 L
Molarity = 0.01 M
Now, you can plug the molarity of the acid into the pH equation.
pH = -log[H⁺]
pH = -log[0.01]
pH = 2
