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Studentka2010 [4]
3 years ago
10

Which molecule has a central carbon with four different components around it

Physics
1 answer:
sasho [114]3 years ago
3 0
Methane


The many covalent bonds between the atoms in hydrocarbons store a great amount of energy, which releases when these molecules burn
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A 500 N force accelerates an object at 20 m s-2. What is its mass?
avanturin [10]

<u>Answer</u>: The mass of the object is 25kg.

The given question deals with Newton's second law of motion and its applications.

<u>Explanation:</u> Given force, F=500N

                                 acceleration, a=20 m/s^{2}

  From Newton's 2nd law of motion , we have

                             F=ma where m=mass of the object

                         ⇒500=m×20

                         ⇒m=500/20=25

                 ∴ Mass of the object is 25 kg .

<u> </u><u>Reference Link: </u>brainly.com/question/1141170

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8 0
2 years ago
A sculpture is suspended in equilibrium by two cables, one from a wall and the other
aleksandrvk [35]

Answer:

T_1=6655.295917 \approx 6655.3N

Explanation:

From the question we are told that

Angle of cable 2 \theta=37.0\textdegree

Weight of sculpture W=5000 N

Generally the Tension from cable 2 T_2 is mathematically given by

   T_2sin37\textdegree=5000N

   T_2=5000N/sin37\textdegree

   T_2=8308.2N

Generally the Tension from Cable 1 T_1 is mathematically given by

   T_1=T_2 cos37\textdegree

   T_1=8308.2* cos 37\textdegree

   T_1=6655.295917 \approx 6655.3N

7 0
3 years ago
Lifting a stone block 146m to the top of the Great Pyramid required 146,000 J of work. How much work was done to lift the block
ASHA 777 [7]
B is your answer to the question
3 0
3 years ago
How fast can a 4000 kg truck travel around a 70 m radius turn without skidding if its tires share a 0.6 friction coefficient wit
aleksley [76]

Answer:

Velocity of truck will be 20.287 m /sec

Explanation:

We have given mass of the truck m = 4000 kg

Radius of the turn r = 70 m

Coefficient of friction \mu =0.6

Centripetal force is given  F=\frac{mv^2}{r}

And frictional force is equal to F_{frictional}=\mu mg

For body to be move these two forces must be equal

So \frac{mv^2}{r}=\mu mg

v=\sqrt{\mu rg}=\sqrt{0.6\times 70\times 9.8}=20.287m/sec

7 0
3 years ago
Jana is observing a young autistic boy in a preschool classroom. Her job is to note each time the boy gets up from his chair wit
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The answer is tallying
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