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vodka [1.7K]
3 years ago
6

How he will move in terms of the forces acting on him

Physics
1 answer:
Viefleur [7K]3 years ago
6 0
A ball is moving upwards and rightwards towards its peak. The ball .... since the only horizontal force acting upon it is a "left-ward" force.
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Using monochromatic light of 410 nm wavelength, a single thin slit forms a diffraction pattern, with the first minimum at an ang
VLD [36.1K]

Answer:

c. 307 nm

Explanation:

angular position of first dark fringe =  λ / d ,   λ is wavelength and  d is width of slit .

(40 x π ) / 180 = 410 / d

angular position of second  dark fringe =  2 x λ / d ,   λ is wavelength and  d is width of slit .

(60 x π ) / 180 = 2 x λ / d

Dividing these equations

60 / 40 =  2 x λ / 410

λ = 307.5 nm.

5 0
3 years ago
To reduce inductive reactance, what devices are normally placed on transmission or distribution lines?
UkoKoshka [18]

Answer : Capacitors

Explanation : Capacitors are normally  placed on transmission or distribution lines when to reduce inductive reactance.

This is because it enhances electromechanical and voltage stability , limit voltage dips at network nodes and reduces the power loss.

So, we can say that inductive reactance normally replace by the capacitors.



4 0
3 years ago
If the mass of each ball is 12 kg and they experience a gravitational force of magnitude 2.00
VLD [36.1K]

Answer:

{2 \times 10} - 7 = 12 {}^{2}  \div x \\ x = 2 \times 10 - 7 \div 12 {}^{2}

I'm just in jss2 but I read physics. this is what I think

7 0
3 years ago
A woman pushes an oak chest across an oak floor at a constant speed of 0.450 m/s. The chest has a mass of 40.0 kg, and the coeff
natima [27]

Answer:

A. 243 N

Explanation:

Friction is the force that opposes the relative motion between systems that are in contact.

This friction force that opposes the motion of the oak chest across the oak surface will be equal and opposite to that exerted by the woman.

First find the normal force which is the force that would point directly upwards to support weight of the block.

Normal force, N= mg where m is the mass of the chest and g is the acceleration due to gravity.

Given m=40 kg and g=9.80 m/s²

N force=40×9.80 =392N

Then find the force of friction which is given by the formula;

<em>F=μN where μ is friction coefficient for the  oak chest  and N is the normal force on the chest</em>

Given <em>μ</em>=0.620  and N force = 392 N then it will be;

F=0.620× 392 =243.04 N

Answer : 243 N

6 0
3 years ago
Automobile traveling at 65 mph constant on the road described below. Find rate at which radar must rotate when theta = 15 deg. A
Finger [1]

Answer:

The rate at which radar must rotate is 0.335 rad/s.

Explanation:

Given that,

Velocity = 65 m/h = 29.0576 m/s

Angle = 15°

Suppose, the radius given by

r=(100\cos2\theta)\ m

We need to calculate the rate at which radar must rotate

Using formula of linear velocity

v=r\omega

\omega=\dfrac{v}{r}

Where, v = velocity

r = radius

Put the value into the formula

\omega=\dfrac{29.0576}{100\cos30}

\omega=0.335\ rad/s

Hence, The rate at which radar must rotate is 0.335 rad/s.

3 0
3 years ago
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