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3 years ago

A wave with high amplitude _____.

Physics

2 answers:

Ray Of Light [21]3 years ago

5 0

Answer: The correct answer is B.

Explanation:

Amplitude is the maximum displacement of the particle from the position of the equilibrium. The amplitude of the wave is related to the energy. Energy of the wave is directly proportional to the square of the amplitude of the wave.

Higher the amplitude of the wave, higher will be the energy of the wave. Lower will be the amplitude, lower will be the energy of the wave.

Therefore, a wave with high amplitude has more energy than a wave with low amplitude.

Archy [21]3 years ago

4 0

B) Has more energy than a wave with low amplitude..... hope it helps :)

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If a topographic map included a 6,000 ft. mountain next to an area of low hills, which would best describe the contour lines on

VMariaS [17]

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3 years ago

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faust18 [17]

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3 years ago

.In a bizarre but harmless accident, Superman fell from the top of the Eiffel Tower. How fast was Superman traveling when he hit

ELEN [110]

Answer:

(7.8) x (9.8 m/s) = 76.44 m/s

during the time he spent falling.

Since his falling speed was zero when he 'stepped' off of the top,

he hit the ground at 76.44 m/s.

That's about 170 miles per hour.

I'll bet he left one serious crater!

I hope this helps too! :D

Explanation:

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3 years ago

Suppose a gliding 2-kg cart bumps into, and sticks to, a stationary 5-kg cart. If the speed of the gliding cart before the colli

Thepotemich [5.8K]

Answer:

Therefore,

Final velocity of the coupled carts after the collision is

$v_{f}=4\ m/s$

Explanation:

Given:

Mass of Glidding Cart = m₁ = 2 kg

Mass of Stationary Cart = m₂ = 5 kg

Initial velocity of Glidding Cart = u₁ = 14 m/s

Initial velocity of Stationary Cart = u₂ = 0 m/s

To Find:

Final velocity of the coupled carts after the collision = $v_{f}=?$

Solution:

Law of Conservation of Momentum:

For a collision occurring between two objects in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.

It is denoted by "p" and given by

Momentum = p = mass × velocity

Hence by law of Conservation of Momentum we hame

Momentum before collision = Momentum after collision

Here after collision both are stuck together so both will have same final velocity,

$m_{1}\times u_{1}+m_{2}\times u_{2}=(m_{1}+m_{2})\times v_{f}$