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vredina [299]
3 years ago
8

A wave with high amplitude _____.

Physics
2 answers:
Ray Of Light [21]3 years ago
5 0

Answer: The correct answer is B.

Explanation:

Amplitude is the maximum displacement of the particle from the position of the equilibrium. The amplitude of the wave is related to the energy. Energy of the wave is directly proportional to the square of the amplitude of the wave.

Higher the amplitude of the wave, higher will be the energy of the wave. Lower will be the amplitude, lower will be the energy of the wave.

Therefore, a wave with high amplitude has more energy than a wave with low amplitude.

Archy [21]3 years ago
4 0
B) Has more energy than a wave with low amplitude..... hope it helps :)
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An electron shell can hold 2(n^2) electrons (technically) where n is the shell number, i.e. shell 1 can hold 2, shell 2 can hold 8, 3 holds 18 and so on.
The atomic number of Nitrogen is 7, i.e. it has 7 electrons (to match its 7 protons, assuming it isn't an ion).

With the atomic number, you simply start from shell 1 and work out. So we put 2 electrons in shell 1, leaving us with 5 left. Shell 2 can hold 6 so we can fit all 5 in.

In other words, you should have 2 electron shells on the atom, shell 1 with 2 e- and shell 2 with 5 e-.
3 0
3 years ago
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As you drive away from a radio transmitter, the radio signal you receive from the station is shifted to longer wavelengths.
mylen [45]

Answer:

True

Explanation:

{Apparent}.wavelength = (True.wavelength)(1 +\frac{recession.velocity}{wave.speed})

As one drive away from the radio station, the recession velocity increases and causes the apparent wavelength to increase accordingly, which in turn causes the True wavelength received from the radio station to increase as well because of their direct relationship as shown in the equation above.

5 0
3 years ago
A non living factor in an ecosystem
I am Lyosha [343]

Answer:

Explanation:Abiotic is the answer.

8 0
3 years ago
Am radio signals are broadcast at frequencies between 550 khz and 1600 khz and travel 2.99792 × 108 m/s. What is the shortest am
Rus_ich [418]

Answer:

187.37 m

Explanation:

The wavelength of an electromagnetic wave is given by:

\lambda=\frac{c}{f}

where

c is the speed of light

f is the frequency

We see that the wavelength is inversely proportional to the frequency: this means that the shortest am wavelength will occur at the highest am frequency, which is

f=1600 kHz = 1600 \cdot 10^3 Hz

And substituting also the speed of light

c=2.99792 \cdot 10^8 m/s

We find the wavelength:

\lambda=\frac{2.99792 \cdot 10^8 m/s}{1600\cdot 10^3 Hz}=187.37 m

5 0
3 years ago
The lens of a telescope has a diameter of 25 cm. You are using it to look at two stars that are 2 × 1017 m away from you and 6 ×
vagabundo [1.1K]

Answer:

a)It is NOT possible using this telescope, to see the two stars as separate stars

b)d_{min} =28.466m

Explanation:

From the question we are told that:  

Diameter of lens,d = 25 cm \approx 0.25 m

Distance from both star D_f= 2*10^{17} m

Distance between both stars D_b= 6*10^9 m

Wavelength of light \lambda =700 nm \approx 700*10^-9 m

Generally the equation for angle subtended by the two stars at the lens  is mathematically given by

 \theta=\frac{D_f}{D_b}

 \theta=\frac{6*10^9}{2*10^{17}}

 \theta=3.0*10^{-8} rad

Generally the equation for minimum angular separation of two object is mathematically given by

\theta_{min} = 1.22*\lambda/d  

\theta_{min}= \frac{1.22*700*10^-9}{0.25}  

\theta_{min}= 3.416*10^-^6 rad

Therefore

 \theta < \theta_{min}

3.0*10^{-8} rad<  3.416*10^-^6 rad

It is NOT possible using this telescope, to see the two stars as separate stars

b)

Generally the equation for minimum diameter of the lens is mathematically given by

  d_{min} =\frac{ 1.22*\lambda}{\theta}

  d_{min} =\frac{ 1.22*700*10^{-9}}{3*10^{-8}}

  d_{min} =28.466m

3 0
3 years ago
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