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2 years ago

A wave with high amplitude _____.

Physics

2 answers:

Ray Of Light [21]2 years ago

5 0

Answer: The correct answer is B.

Explanation:

Amplitude is the maximum displacement of the particle from the position of the equilibrium. The amplitude of the wave is related to the energy. Energy of the wave is directly proportional to the square of the amplitude of the wave.

Higher the amplitude of the wave, higher will be the energy of the wave. Lower will be the amplitude, lower will be the energy of the wave.

Therefore, a wave with high amplitude has more energy than a wave with low amplitude.

Archy [21]2 years ago

4 0

B) Has more energy than a wave with low amplitude..... hope it helps :)

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A cup of coffee is sitting on a table in a train that is moving with a constant velocity. The coefficient of static friction bet

Vikki [24]

Answer:

a = 2.94 m/s²

Explanation:

In order for the cup not to slip, the unbalanced force on cup must be equal to the frictional force:

Unbalanced Force = Frictional Force

ma = μR = μW

ma = μmg

a = μg

where,

a = maximum acceleration for the cup not to slip = ?

μ = coefficient of static friction = 0.3

g = acceleration due to gravity = 9.8 m/s²

Therefore,

a = (0.3)(9.8 m/s²)

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3 years ago

you are flying on an airplane and you overhear two pasengers comment that flight attendants must be very skiled, one says "when

s344n2d4d5 [400]

How do you get out of a room with only a mirror and a table?

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Thought you would like that.

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2 years ago

Please help (choose a b or c)

Dafna11 [192]

I GEUSS A and COM is correct answer to this question

3 0

3 years ago

Read 2 more answers

Suppose the polar bear was running on land instead of swimming. If the polar bear runs at a speed of about 8.3 m/s, how far will

olga_2 [115]

Answer:

298800 m

Explanation:

$v = \frac{d}{t}$

V=speed

d=distance

t=time

$d = vt$

Change hours to seconds

It will be 36000s

8.3m/s * 36000s

=298800m

8 0

3 years ago

Suppose an object is launched from a point 320 feet above the earth with an initial velocity of 128 ft/sec upward, and the only

Ne4ueva [31]

Answer:

(a)Therefore the highest altitude attained by the object is =576 ft .

(b)Therefore the object takes 6 sec to fall to the ground.

Explanation:

Initial velocity: Initial velocity is a velocity from which an object starts to move.

u is usually used for notation of initial notation.

Final velocity: Final velocity is a velocity of an object after certain second from starting.

The final velocity is denoted by v.

Acceleration: The difference of final velocity and initial velocity per unit time

The S.I unit of acceleration is m/s².

(a)

Given that u= 128 ft\sec and g = 32 ft/sec².

At highest point the velocity of the object is 0 i.e v=0

Since the displacement is opposite to the gravity.

Therefore acceleration( a)= -g = -32 ft/sec².

To find the time this to happen we use the following formula

$v=u+at$

Here v=0

⇒0=128+(-32) t

⇒32t=128

⇒t = 4 sec

To determine the height we use the following formula

$s=ut+\frac{1}{2} at^2$

$\Rightarrow s= (128\times4)+\frac{1}{2}\times (-32) \times4^2$

⇒s= 256 ft

Therefore the highest altitude attained by the object is =(320+256)ft=576 ft .

(b)

At the highest point the velocity of the object is 0.

so u=0. a=g= 32 ft/sec² [ since the direction of gravity and the displacement are same] s= 576 ft

To determine the time to fall we use the following formula

$s=ut+\frac{1}{2} at^2$

$\Rightarrow 576 = (0\times t)+\frac{1}{2} \times 32 \times t^2$

$\Rightarrow 16\times t^2=576$

$\Rightarrow t^2=\frac{576}{16}$

$\Rightarrow t^2=36$

⇒t=6 sec

Therefore the object takes 6 sec to fall to the ground.

8 0

2 years ago