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3 years ago

If you drew magnetic field lines for this bar magnet, which statement would be true.

Physics

2 answers:

Ulleksa [173]3 years ago

7 0

Answer:

The awnser is B

Explanation:

xxTIMURxx [149]3 years ago

4 0

Answer: B. Field lines loop around the magnet starting at the north pole and ending at the south pole.

Explanation:

A magnet has two poles: North pole and South pole. Magnetic field lines are imaginary lines where magnetic force is exerted. Magnetic field lines form closed loops around the magnet. These lines start from North pole and terminate at south pole. The strength of the magnet is maximum near the poles. The lines are unique and do not cross each other.

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A car is traveling due north at 23.6 m>s.

alexira [117]

A car is traveling due north at 23.6 m>s.

Find the velocity of the car after 7.10 s if its

acceleration is

The acceleration is known to be: a(t) = 1.7 m/s2.

We must integrate over time to obtain the velocity function, and the results are:

v(t) = (1.7m/s^2)

*t + v0

If we suppose that we begin at 23.6 m/s, then the initial velocity is: v0 = 23.6 m/s, where v0 is the beginning velocity.

The velocity formula is then: v(t) = (1.7m/s2).

*t + 23.6 m/s

We now seek to determine the value of t such that v(t) = 27.8 m/s.

Consequently, v(t) = 27.8 m/s = (1.7 m/s2)

*t + 23.6 m/s = (1.7 m/s2) 27.8 m/s - 23.6 m/s

t = 2.5 seconds when *t 4.2 m/s = (1.7 m/s/2)

At such acceleration, 2.5 seconds are required.

To learn more about acceleration Visit :

brainly.com/question/19599982

#SPJ9

4 0

2 years ago

If you take a bar magnet with both n & s poles and cut it in half, you get

creativ13 [48]

I think you get half of the magnetic field and that means half the power of the magnetic field.

7 0

3 years ago

3. Three blocks of masses m, 2m and 3m are suspended from the ceiling using ropes as shown in diagram. Which of the following co

Alja [10]

Answer:

The correct option is d: T₁ > T₂ > T₃.

Explanation:

Let's evaluate each tension.

Case T₃.

$T_{3} - W_{3} = 0$

For the system to be in equilibrium, the algebraic sum of the tension force (T) and the weight (W) must be equal to zero. The minus sign of W is because it is in the opposite direction of T.

$T_{3} = W_{3}$

Since W₃ = mg, where m is for mass and g is for the acceleration due to gravity, we have:

$T_{3} = W_{3} = mg$ (1) Case T₂.

$T_{2} - (T_{3} + W_{2}) = 0$

$T_{2} = T_{3} + W_{2}$ (2)

By entering W₂ = 2mg and equation (1) into eq (2) we have:

$T_{2} = T_{3} + W_{2} = mg + 2mg = 3mg$

Case T₁.

$T_{1} - (T_{2} + W_{1}) = 0$

$T_{1} = T_{2} + W_{1}$ (3)

Knowing that W₁ = 3mg and T₂ = 3mg, eq (3) is:

$T_{1} = 3mg + 3mg = 6mg$

Therefore, the correct option is d: T₁ > T₂ > T₃.

I hope it helps you!

6 0

3 years ago

Read 2 more answers

1 2 3 4 5 6 7 8 9 10

7nadin3 [17]

Answer:

<h2>C. 0.55 m/s towards the right</h2>

Explanation:

Using the conservation of law of momentum which states that the sum of momentum of bodies before collision is equal to the sum of the bodies after collision.

Momentum = Mass (M) * Velocity(V)

BEFORE COLLISION

Momentum of 0.25kg body moving at 1.0m/s = 0.25*1 = 0.25kgm/s

Momentum of 0.15kg body moving at 0.0m/s(body at rest) = 0kgm/s

AFTER COLLISION

Momentum of 0.25kg body moving at x m/s = 0.25* x= 0.25x kgm/s

x is the final velocity of the 0.25kg ball

Momentum of 0.15kg body moving at 0.75m/s(body at rest) =

0.15 * 0.75kgm/s = 0.1125 kgm/s

Using the law of conservation of momentum;

0.25+0 = 0.25x + 0.1125

0.25x = 0.25-0.1125

0.25x = 0.1375

x = 0.1375/0.25

x = 0.55m/s

Since the 0.15 kg ball moves off to the right after collision, the 0.25 kg ball will move at 0.55 m/s towards the right

4 0

3 years ago

Which does not represent a change in velocity?

alina1380 [7]

Answer:

A balloon is floating up into the air at 1 m/s.

Explanation:

Velocity is the displacement divided by the time;

Velocity = $\frac{displacement}{time}$

It is a vector quantity that has magnitude and direction.

The choice that shows a change in direction is a correct specification of velocity.

A balloon floating up into the air at 1m/s shows no directional change.

7 0

3 years ago