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Tems11 [23]
3 years ago
9

Scientific evidence is most likely to be consistent if it is based on data from

Chemistry
2 answers:
ladessa [460]3 years ago
6 0

Answer:

Random samples

Explanation:

It needs to be random so that there isn't bias that would skew the consistency

tamaranim1 [39]3 years ago
5 0

Answer:

A

Explanation:

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Can some one help whith these
MA_775_DIABLO [31]

Answer:

what is this pdf I cannot see your question

5 0
3 years ago
Read 2 more answers
Determine the molecular geometry about the left carbon atom in ch3co2ch3.
Elanso [62]

Molecular geometry about the left carbon atom in CH₃CO₂CH₃ is tetrahedral.

The geometry around left carbon that is CH₃ is tetrahedral.

As the hybridization around left carbon is sp³ that shows its geometry should be tetrahedral and as there are 4 ligands around carbon and there is no lone pair present so the geometry is tetrahedral. So, the molecular geometry about the left carbon atom in CH₃CO₂CH₃ is tetrahedral.



4 0
3 years ago
Read 2 more answers
Consider the reaction CaCN2 + 3 H2O → CaCO3 + 2 NH3 . This reaction has a 75.6% yield. How many moles of CaCN2 are needed to obt
kherson [118]

Answer: Thus 0.724 mol of CaCN_2 are needed to obtain 18.6 g of NH_3

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} NH_3=\frac{18.6g}{17g/mol}=1.09moles

CaCN_2+3H_2O\rightarrow CaCO_3+2NH_3

According to stoichiometry :

2 moles of NH_3 are produced by = 1 mole of CaCN_2

Thus 1.09 moles of NH_3 will be produced by =\frac{1}{2}\times 1.09=0.545moles  of CaCN_2

But as yield of reaction is 75.6 %, the amount of CaCN_2 needed is =\frac{0.545}{75.6}\times 100=0.724

Thus 0.724 mol of CaCN_2 are needed to obtain 18.6 g of NH_3

3 0
3 years ago
What would happen if you used a warm washcloth if you had a fever.
aivan3 [116]
You will feel way better because in our class we learned that lukewarm baths are good for fevers and warm washcloths :)
3 0
3 years ago
How many molecules are in 3 moles of potassium bromide (KBr)
sattari [20]

Answer:

Your strategy here will be to use the molar mass of potassium bromide,

KBr

, as a conversion factor to help you find the mass of three moles of this compound.

So, a compound's molar mass essentially tells you the mass of one mole of said compound. Now, let's assume that you only have a periodic table to work with here.

Potassium bromide is an ionic compound that is made up of potassium cations,

K

+

, and bromide anions,

Br

−

. Essentially, one formula unit of potassium bromide contains a potassium atom and a bromine atom.

Use the periodic table to find the molar masses of these two elements. You will find

For K:

M

M

=

39.0963 g mol

−

1

For Br:

M

M

=

79.904 g mol

−

1

To get the molar mass of one formula unit of potassium bromide, add the molar masses of the two elements

M

M KBr

=

39.0963 g mol

−

1

+

79.904 g mol

−

1

≈

119 g mol

−

So, if one mole of potassium bromide has a mas of

119 g

m it follows that three moles will have a mass of

3

moles KBr

⋅

molar mass of KBr



119 g

1

mole KBr

=

357 g

You should round this off to one sig fig, since that is how many sig figs you have for the number of moles of potassium bromide, but I'll leave it rounded to two sig figs

mass of 3 moles of KBr

=

∣

∣

∣

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

360 g

a

a

∣

∣

−−−−−−−−−

Explanation:

<em>a</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em>:</em><em> </em><em>3</em><em>6</em><em>0</em><em> </em><em>g</em><em> </em>

6 0
3 years ago
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