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Tems11 [23]
3 years ago
9

Scientific evidence is most likely to be consistent if it is based on data from

Chemistry
2 answers:
ladessa [460]3 years ago
6 0

Answer:

Random samples

Explanation:

It needs to be random so that there isn't bias that would skew the consistency

tamaranim1 [39]3 years ago
5 0

Answer:

A

Explanation:

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How many moles are present in 100 grams of potassium?
spayn [35]

Answer:

39.0983.

Explanation:

4 0
3 years ago
I can't find the answer for number 9/10 pleas help
kondaur [170]
(10)an object  will continue  to travel at a constant speed unless acted by an unbalanced  force  according to newtons second law every force acted on a body has a equal and opposite reaction so the speed and the direction of the object will change.

(9) balanced force (i think so )

hope this is what you needed the 10th one is for understanding you can shorten it after reading and i think what i have written is not wrong :P:P:P;p:P:):):):D=) for the ninth one i am not sure but i think so :P:)=)


8 0
3 years ago
Read 2 more answers
The cells of a tomato contain mostly an aqueous solution of sugar and other substances. If a typical tomato freezes at -2.5 °C,
DIA [1.3K]

Answer:

1.35 m

Explanation:

We can solve this problem by using the <em>freezing point depression formula</em>:

  • ΔT = Kf * m * i

Where:

  • ΔT is the temperature difference between the freezing point of the pure solvent (water) and the solution. In this case it is (<em>0 °C - -2.5 °C = 2.5 °C</em>).
  • Kf is the cryoscopic constant, <em>for water it is 1.853  °C*kg/mol.</em>
  • m is the molality.
  • i is the van't Hoff factor, <em>as sugar does not dissociate in water, it has a value of 1</em>.

We <u>input the data</u>:

  • 2.5 °C = 1.853 °C*kg/mol * m * 1

And <u>solve for m</u>:

  • m = 1.35 m
6 0
3 years ago
Consider the following generic chemical equation.
makvit [3.9K]

Answer:

\fbox{ A) A  \:  is  \:  limiting \: reactant }

\fbox{ B) B  \:  is  \:  limiting \: reactant }

\fbox{ C) A  \:  is  \:  limiting \: reactant }

\fbox{ D) A  \:  is  \:  limiting \: reactant }

Explanation:

<em>Given equation:</em>

<em>A+3B \rightarrow \: C</em>

<em>To </em><em>find:</em>

Limiting reactant for corresponding number of moles=?

<em>Solution:</em>

We know that the liming reactant is any atom, ion or molecule which is completely consumed during a reaction and other reactant is still left in reactant vessel.

For the given reaction A+3B→C

for every one mole of A three moles of B are required.

﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌

in A) there is one mole of A and 4 mole of B,

if 1 mole of A will react with 3 moles of B, 1 mole of B will be still there in reaction, the reactant was completely consumed is A which is limiting reactant.

﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌

in B) there is 2 mole of A and 3 mole of B,

if 1 mole of A will react with 3 moles of B, 1 mole of A will be still there in reaction, the reactant was completely consumed is B which is limiting reactant.

﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌

in C) there is 0.5 mole of A and 1.6 mole of B

if one mole of A requires three moles of B to complete the reaction then,

0.5 moles of A will require 1.5 moles of B

if 0.5 mole of A will react with 1.6 moles of B, 0.1 mole of B will be still there in reaction, the reactant was completely consumed is A which is limiting reactant.

﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌

in D) there is 24 mole of A and 72 mole of B

if one mole of A requires three moles of B to complete the reaction then,

24 moles of A will require 72 moles of B.

if 24 mole of A will react with 75 moles of B, 3 mole of B will be left over in reaction, the reactant was completely consumed is A which is limiting reactant.

﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌

\fbox{ A) A  \:  is  \:  limiting \: reactant }

\fbox{ B) B \:  is \:  limiting \:  reactant }

\fbox{ C) A  \:  is  \:  limiting \: reactant }

\fbox{ D) A  \:  is  \:  limiting \: reactant }

<em><u>Thanks for joining brainly community.</u></em>

5 0
2 years ago
Which type of variable is “measured to see its response to the change in another variable”? a independent b controlled c constan
Ludmilka [50]
Dependent variable cause it's the data of the experiment
4 0
3 years ago
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