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Musya8 [376]
3 years ago
15

A force of 9.00 newtons acts at an angle of 19.0° to the horizontal. What is its component in the horizontal direction?

Physics
2 answers:
g100num [7]3 years ago
5 0
It would be helpful if you draw the figure of the problem. You will see that a right triangle would be constructed by the problem where 19.0 is the angle between the hypotenuse and the base of the triangle. It is said that the force acting is said to be 9.0 N  at the said angle to the horizontal. Using trigonometric relations,

cos 19 = adjacent / hypotenuse = horizontal component / 9
horizontal component = 8.51 N
hoa [83]3 years ago
5 0

Answer:

8.51 N

Explanation:

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Response:

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F_0 = \dfrac{M \cdot g \cdot sin(37 ^{\circ})}{2 \cdot cos(37 ^{\circ})}} = \dfrac{M \cdot g \cdot tan(37 ^{\circ})}{2}  \approx  \mathbf{0.377  \cdot M \cdot g}

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<u />

Learn more about equilibrium of forces here:

brainly.com/question/6995192

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