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tensa zangetsu [6.8K]
3 years ago
11

Microwave ovens emit microwave energy with a wavelength of 12.2 cm. What is the energy of exactly one photon of this microwave r

adiation?
Physics
1 answer:
Iteru [2.4K]3 years ago
5 0

Answer:

1.63\cdot 10^{-24} J

Explanation:

The energy of a photon is given by:

E=\frac{hc}{\lambda}

where

h is the Planck constant

c is the speed of light

\lambda is the wavelength of the photon

In this problem, we have a microwave photon with wavelength

\lambda=12.2 cm=0.122 m

Substituting into the equation, we find its energy:

E=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{0.122 m}=1.63\cdot 10^{-24} J

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Answer:

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the height of seven falls in colorado is 5/2 the height of twin falls in idahi. the sum of the two heights is 420 ft. find the h
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