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nexus9112 [7]
3 years ago
12

What is an incident wave,and a normal

Physics
1 answer:
Dafna1 [17]3 years ago
5 0

Answer:

An incident wave is a current or voltage wave that travels through a transmission line from the generating source towards the load. It becomes incident when it arrives at a discontinuity or another medium with different propagation characteristics. Wave normal. A unit vector which is perpendicular to an Equiphase surface of a wave, and has its positive direction on the same side of the surface as the direction of propagation.

Explanation:

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A statue of unknown volume and density is suspended from a string. When suspended in air, the tension in the string is Tair; how
Dafna11 [192]

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.  

7 0
3 years ago
A 320-m length of wire stretches between two towers and carries a 120-a current. determine the magnitude of the force on the wir
MissTica
Information provided:
Length of wire, L = 320 m
Current through the wire, I = 120 Amps
Earth's magnetic field acting on the wire, B = 5.0*10^-5 T
Angle at which the magnetic field acts, Ф = 60°

By definition;
Force on the wire, F = LBI Sin Ф

Substituting;
F = 320*5*10^-5*120*Sin 60 = 1.663 N
3 0
3 years ago
Bill is farsighted and has a near point located 125 cm from his eyes. Anne is also farsighted, but her near point is 75.0 cm fro
Arisa [49]

Answer:

a) The closest object Anne can see, while wearing Bill's glasses is at approximately 22.39 cm relative to her eyes

b) The closest object Bill can see while wearing Anne's glasses is at approximately 26.38 cm relative to his eyes

Explanation:

The point where Bill has a near point = 125 cm

The point where Anne has a near point = 75.0 cm

Their vision are both corrected to the normal near point = 25.0 cm

The distance of their glasses from the eye, d = 2.0 cm

The lens formula is presented as follows;

\dfrac{1}{f} =\dfrac{1}{d_0} +\dfrac{1}{d_i}

The required distance of the of the object from Bill's glass, d_{oB} = 25 cm - 2.0 cm = 23.0 cm

The distance of the of the image from Bill's glass, d_{iB} = -(125 cm - 2.0 cm) = -123 cm

Therefore, for Bill, we have;

\dfrac{1}{f_B} =\dfrac{1}{d_{0B}} +\dfrac{1}{d_{iB}}

Plugging in the values gives;

\dfrac{1}{f_B} =\dfrac{1}{23} -\dfrac{1}{123} = \dfrac{100}{2,829}

Therefore;

f_B = 2,829/100 cm = 28.29 cm

The required distance of the of the object from Anne's glass, d_{oA} = 25 cm - 2.0 cm = 23.0 cm

The distance of the of the image from Anne's glass, d_{iA} = -(75 cm - 2 cm) = -73 cm

The focal length for Anne is therefore;

\dfrac{1}{f_A} =\dfrac{1}{d_{0A}} +\dfrac{1}{d_{iA}}

Plugging in the values gives;

\dfrac{1}{f_A} =\dfrac{1}{23} -\dfrac{1}{73} = \dfrac{50}{1,679}

Therefore, we have;

f_A = 1,679/50 cm = 33.58 cm

a) When Anne wears Bill's lasses, we have;

\dfrac{1}{f_B} =\dfrac{1}{d_{0A}} +\dfrac{1}{d_{iA}}

Therefore, we get;

\dfrac{1}{28.29} =\dfrac{1}{d_{0A}} -\dfrac{1}{73}

\dfrac{1}{d_{0A}}  = \dfrac{1}{28.29} + \dfrac{1}{73} = \dfrac{10,129}{206,517}

d_{0A} ≈ 20.39 cm

The distance of the closest object Anne can see, from her eye, d_{oe} =  d_{0A} + d

∴ d_{oe} ≈ 20.39 cm + 2.0 cm = 22.39 cm

The distance of the closest object Anne can see, from her eye, d_{oe} ≈ 22.39 cm

b) The closest object that can be seen when Bill wears Anne's glasses, we have;

\dfrac{1}{f_A} =\dfrac{1}{d_{0B}} +\dfrac{1}{d_{iB}}

Therefore;

\dfrac{1}{33.58} =\dfrac{1}{d_{0B}} -\dfrac{1}{123}

\dfrac{1}{d_{0B}} = \dfrac{1}{33.58} +\dfrac{1}{123} = \dfrac{7,829}{206,517}

∴ d_{oB} ≈ 26.38 cm

The closest object Bill can see while wearing Anne's glasses,  d_{oB} ≈ 26.38 cm.

6 0
2 years ago
The mass of an object is 100 mg. What is the object's mass in kg? Please show some work to help explain it.
Trava [24]

100 mg

100 * 10^-3 g

0.1 g

0.1 * 10^-3 kg

10^-4 kg

- 1 kg = 1000 g

- 1 g = 1000 mg

6 0
3 years ago
Read 2 more answers
Which of the following has the most inertia, if they all travel at 5 m/s?
WARRIOR [948]

Answer:

D

Explanation:

It has more mass

6 0
3 years ago
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