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ad-work [718]
3 years ago
15

How does Newtons first law of motion relate to planetary motion

Physics
1 answer:
Varvara68 [4.7K]3 years ago
3 0
Newton's Laws<span>. </span>Kepler's Laws<span> are wonderful as a description of the </span>motions<span> of the </span>planets<span>. However, they provide no explanation of why the </span>planets<span> move in this way. Moreover, </span>Kepler's<span> Third </span>Law<span> only works for </span>planets<span> around the Sun and does not apply to the Moon's orbit around the Earth or the moons of Jupiter.

!!hope this helpful to you!!
please mark this a !!brainliest answer!!</span>
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A body 'A' of mass 1.5kg travelling along the positive X-axis with speed of 4.5m/s collides with another body 'B' of mass 3.2kg,
xz_007 [3.2K]
I already answered this question. 
Please refer to this link brainly.com/question/8743596.
6 0
3 years ago
If transpiration didn't take place, would water be able to enter the roots of the plant? Explain your reasoning
s2008m [1.1K]

Answer:

If transpiration didn't take place water would still be able to enter the roots of a plant

Explanation:

transpiration is the process of water leaving from living organisms to the atmosphere, therefore, if transpiration didn't occur the water would not transpire to the atmosphere and would remain in the root but water absorption would not change because it is a biological need for the living organism as such

3 0
3 years ago
PLEASE HELP!!! WOULD REALLY APPRECIATE!
Eva8 [605]

Answer:

a. slope=rise/run

rise=0.02

run=-2

determined using the point (3,0.08) and (1,0.1) on the graph

slope=0.02/-2

= -0.01 or -1/100

b.area= area of trapizoid+ rectangle

((0.07+0.11)÷2)×4+1×0.07

0.36+0.07

=0.43$

c. the area represent the total cost after 5 hours

PLEASE MARK BRAINLIEST

3 0
2 years ago
Which of the following is considered a physical change?
zmey [24]

Answer:

C)evaporating of water

Explanation:that is because waters physical property is lost after evaporating

4 0
3 years ago
Read 2 more answers
The level of water in an olympic size swimming pool (50.0 meters long, 25.0 meters wide, and about 2.00 meters deep) needs to be
Goshia [24]
<span>We need to start by finding the surface area of the pool.
50 meters multiplied by 25 meters gives us 1250 square meters.
1250 square meters multiplied by .065 (6.5 cm in meters) gives us a volume of 81.25 cubic meters of water that needs to be pumped out of the pool.

There are 1000 liters in a cubic meter so this is 81250 liters. Divide by 4.2 to find the number of seconds required to pump out this much water and we get 19345.2 seconds. This equals approximately 5.37 hours.</span>
4 0
3 years ago
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