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3 years ago

LOOK AT THE PICTURE!! 3 Please answer properly

Physics

2 answers:

Bogdan [553]3 years ago

8 0

Highest point ( A ) ...

Not moving ==> zero kinetic energy
Highest altitude ==> maximum potential energy
------------------------------------
Total energy ==> all potential

Halfway up, halfway down ( B ) ...

Half-altitude ==> half of total energy is potential
Moving ==> some kinetic energy; must be half of total
-----------------------------------------
Total energy ==> same total; half potential, half kinetic

Lowest point ( C ) ...

Minimum altitude ==> zero potential energy
Fastest speed ==> maximum kinetic energy
-----------------------------------------
Total energy ==> same total; no potential, all kinetic

babunello [35]3 years ago

4 0

The total energy at A, B and C is constant and does not change.

At A, all the energy is potential energy. It gets converted partially to kinetic energy at B and is completely converted to kinetic energy at C. At C, all the energy is kinetic energy.

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Plants are made of_________________cells, which have membrain-bound_____.

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3 years ago

A time-varying horizontal force F(t) = At4 + Bt2 acts for 0.500 s on a 12.25-kg object, starting attime t = 1.00 s. In the SI sy

PSYCHO15rus [73]

Answer:

3.82 Ns

Explanation:

Time varying horizontal Force is given as

F(t) = A t⁴ + B t²

F(t) = 4.50 t⁴ + 8.75 t²

Impulse imparted is given as

$I = \int_{0}^{t}Fdt$

$I = \int_{0}^{1}Fdt$

$I = \int_{0}^{1}(4.50 t^{4} + 8.75 t^{2})dt$

$I = ((0.9) (1)^{5} + (2.92) (1)^{3})$

$I = 3.82 N-s$

7 0

3 years ago

Read 2 more answers

Looking straight downward into a rain puddle whose surface is covered with a thin film of gasoline, you notice a swirling patter

Ivanshal [37]

Answer:

Explanation:

Point beneath you forms a beautiful iridescent green

refractive index of Gasoline $n=1.38$

Wavelength of Green light is $\lambda =540\ nm$

Here light first traverse from air(n=1) to gasoline , it reflects from front surface of gasoline(n=1.38) so it suffers a phase change. After this light reflect from rear surface of gasoline and there is a decrease in refractive index(n=1.38 to n=1.33), so there is no phase change occurs .

For constructive interference

$2t=(m+\frac{1}{2})\cdot \frac{\lambda }{n}$

here t= thickness of gasoline film

n=refractive index

for $m=0$

$t=\frac{\lambda }{4n}$

$t=\frac{540}{4\times 1.38}$

$t=97.82\approx 98\ nm$

4 0

3 years ago

If a car driving down the road doubles its speed what happens to its kinetic energy?

ivanzaharov [21]

Answer:

Kinetic energy doubles

7 0

2 years ago

A planet's moon travels in an approximately circular orbit of radius 7.0 ✕ 10⁷ m with a period of 6 h 38 min. Calculate the mass

natka813 [3]

Answer:

3.56×10²⁶ Kg.

Explanation:

Note: The gravitational force is acting as the centripetal force.

Fg = Fc........................... Equation 1

Where Fg = gravitational Force, Fc = centripetal force.

Recall,

Fg = GMm/r²......................... Equation 2

Fc = mv²/r............................. Equation 3

Where M = mass of the planet, m = mass of the moon, r = radius of the orbit and G = Universal gravitational constant.

Substituting equation 2 and 3 into equation 1

GMm/r² = mv²/r

Simplifying the equation above,

M = v²r/G .............................. Equation 4.

The period of the moon in the orbit

T = 2πr/v

Making v the subject of the equation,

v = 2πr/T............................. Equation 5

where r = 7.0×10⁷ m, T = 6 h 38 min = (6×3600 + 38×60) s = (21600+2280) s

T = 23880 s, π = 3.14

v = (2×3.14×7.0×10⁷ )/23880

v = 18409 m/s

Also Given: G = 6.67×10⁻¹¹ Nm²/kg²

Also substituting into equation 4

M = 18409²×7.0×10⁷ /(6.67×10⁻¹¹)

M = 3.56×10²⁶ Kg.

Thus the mass of the planet = 3.56×10²⁶ Kg.

5 0

3 years ago