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2 years ago

LOOK AT THE PICTURE!! 3 Please answer properly

Physics

2 answers:

Bogdan [553]2 years ago

8 0

Highest point ( A ) ...

Not moving ==> zero kinetic energy
Highest altitude ==> maximum potential energy
------------------------------------
Total energy ==> all potential

Halfway up, halfway down ( B ) ...

Half-altitude ==> half of total energy is potential
Moving ==> some kinetic energy; must be half of total
-----------------------------------------
Total energy ==> same total; half potential, half kinetic

Lowest point ( C ) ...

Minimum altitude ==> zero potential energy
Fastest speed ==> maximum kinetic energy
-----------------------------------------
Total energy ==> same total; no potential, all kinetic

babunello [35]2 years ago

4 0

The total energy at A, B and C is constant and does not change.

At A, all the energy is potential energy. It gets converted partially to kinetic energy at B and is completely converted to kinetic energy at C. At C, all the energy is kinetic energy.

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A(n) _______ is a pure substance that can't be broken down into simpler substances by chemical or physical means. A. element

Lyrx [107]

An element is a pure substance that cant be broken down into simpler substances by chemical or physical means. hope it helps :)

3 0

3 years ago

A meter stick is suspended vertically at a pivot point 22 cm from the top end. It is rotated on the pivot until it is horizontal

suter [353]

Answer:

5.82812 rad/s

Explanation:

L = Length of meter stick = 1 m = 100 cm

$m_c$ = The center of mass of the stick = $\frac{L}{2}-0.22=0.5-0.22=0.28\ m$

$\omega$ = Angular velocity

Moment of inertia of the system is given by

$I=I_c+mr^2\\\Rightarrow I=\frac{mL^2}{12}+mr^2\\\Rightarrow I=\frac{m1^2}{12}+m0.28^2\\\Rightarrow I=m(\frac{1}{12}+0.0784)$

As the energy in the system is conserved

$mgh=I\frac{\omega^2}{2}\\\Rightarrow mgh=m(\frac{1}{12}+0.0784)\frac{\omega^2}{2}\\\Rightarrow gh=(\frac{1}{12}+0.0784)\frac{\omega^2}{2}\\\Rightarrow \omega=\sqrt{\frac{2gh}{\frac{1}{12}+0.0784}}\\\Rightarrow \omega=\sqrt{\frac{2\times 9.81\times 0.28}{\frac{1}{12}+0.0784}}\\\Rightarrow \omega=5.82812\ rad/s$

The maximum angular velocity is 5.82812 rad/s

4 0

2 years ago

Ph11_UnitPacket2019

frozen [14]

Let's see

Use snells law

$\\ \rm\Rrightarrow \dfrac{n_1}{n_2}=\dfrac{sini}{sinr}$

$\\ \rm\Rrightarrow \mu=\dfrac{sin30}{sin19.9}$

$\\ \rm\Rrightarrow \mu=0.5/0.34$

$\\ \rm\Rrightarrow \mu=1.47$

It may be glass

3 0

2 years ago

A football player who weighs 550 N stands indoors wearing her football boots. The boot’s

EleoNora [17]

Answer:

183333 Pa

Explanation:

The weight of the football player is : 550 N ,thus the force the player exerts on the floor is 550 N

The area of blades in contact with the floor is = 30cm² = 0.003 m²

Pressure = Force / Area

Pressure = 550 / 0.003

Pressure = 183333 Pa

3 0

2 years ago

local AM radio station broadcasts at a frequency of 685.9 kHz. Calculate the wavelength at which they are broadcasting. Waveleng

natta225 [31]

Answer:

λ = 437 m.

Explanation:

Since a radio wave is a electromagnetic type of wave, it propagates approximately at the same speed of light in vacuum, 3*10⁸ m/s.
As in any wave, there exist a fixed relationship between the propagation speed, the wavelength and the frequency of the radio wave, as follows:

$c = \lambda* f (1)$

Replacing by the values of the speed and the frequency, and solving for the wavelength λ, we get:

$\lambda = \frac{c}{f} =\frac{3e8 m/s}{685.9e31/s} =437 m (2)$

8 0

2 years ago