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Papessa [141]
4 years ago
15

What is the unit used to express the power

Physics
1 answer:
Deffense [45]4 years ago
8 0
The watt<span> (symbol: W) is a unit of power i hope this helps you</span>
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11.) If figure skater spins with a circular acceleration of 275 m/s^2 in a circle 5 poin with a radius of 0.55 meters, calculate
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Answer:

we don't care what ure saying thats absurd

7 0
3 years ago
The relationship between body mass body weight and body density
nordsb [41]

Answer:

The formula for calculating Density is:

= Mass / Volume

From this formula, we can say that the relationship between Mass and Density is a direct one. In other words, if mass is increasing - all else being equal - then density will increase as well.

If mass however was decreasing, density would have to decrease as well.

For example, assume 3 bricks have masses of 5kg, 10kg and 15kg. Also assume that the bricks all have the same volume of 5 m³.

Density of 5kg brick = 5 / 5 = 1 kg/m³

Density of 10kg brick = 10 / 5 = 2kg / m³

Density of 15kg brick = 15 / 5 = 3 kg /m³

<em>Notice how density increases as mass increases and decreases when mass decreases. </em>

7 0
3 years ago
The magnitude of the drag force of air resistance on a certain 20kg object is proportional to its speed. If the object has a ter
Anna11 [10]
Given:
object = 20kg
terminal speed of object = 80 m/s

According to the problem, drag force is proportional to speed, so Fd = kv ; k is some constant
At terminal velocity Vt: Fg = Fdmg = kVtk = mg / Vt = (20.0)(9.8)/(80.0) = 2.45 kg/s
<span>Fd = kv = 2.45v</span>
Fd = 2.45 (30.0) = 73.5 N
8 0
4 years ago
An atomic scientist was studying an atom and through experimentation found that the total negative charge of the
Artist 52 [7]

Answer:

This atom has nine electrons

Explanation:

I just did it and I got it right.

7 0
4 years ago
Josh has a toy car of mass 3 kg tied to a string of length 2 m. He ties the string to a pole and has the toy car drive in a circ
gulaghasi [49]

Part a)

Centripetal acceleration is defined as

a_c = \frac{v^2}{R}

now here we know that

v = 3m/s

R = 2 m

m = 3 kg

now from above formula we have

a_c = \frac{3^2}{2}

a_c = 4.5 m/s^2

Part b)

Maximum possible tension in the string is given as

T = 50 N

now by force equation we have

F = ma

50 = 3 a

a = \frac{50}{3} m/s^2

now again by above formula

\frac{v^2}{R} = \frac{50}{3}

v = \sqrt{\frac{50 \times 2}{3}}

v = 5.77 m/s

5 0
4 years ago
Read 2 more answers
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