Answer:
"H" is a chemical symbol and "H2" is chemical formula.
Answer:
The net force on the stump is 1000 N.
Explanation:
Given that,
Force 1 acting on the truck, (due north)
Force 2 acting on the truck, (due west)
We need to find the net force on the stump. We know that force is a vector quantity. The net force on the stump is given by the the resultant force. It is given by :
F = 1000 N
So, the net force on the stump is 1000 N. Hence, this is the required solution.
The horizontal movement of the rocket is 11m/s, with an acceleration of 1.6m/s². The vertical movement will be downward, with an initial velocity of zero (it was shot horizontally) and a negative acceleration of g (-9.8m/s²)
To see how far the rocket traveled before hitting the ground, let's first figure out the time t at which the rocket hit the ground:
The formula for distance is d= vt + (1/2)at² ,
Where v=initial velocity, d=distance traveled, a=acceleration, and t=time
We want to find how long it took to travel 40 meters (height above the ground), given an initial velocity of 0 and negative acceleration of 9.8
Plugging into the equation:
40 = 0(t) + (1/2) (9.8) (t²) Multiply both sides by (2/9.8)
8.16 = t² Square root of both sides
t= 2.85
The rocket traveled for 2.85 seconds before hitting the ground. Plug this number into our distance formula to find horizontal distance
d= vt + (1/2)at²
d = 11 (2.85) + (1/2) (1.6) (2.85²)
Remember that initial horizonal velocity is 11m/s and horizontal acceleration is 1.6m/s²
Simplify:
d= 31.35 + .8 * 8.16
d = 37.87
The object traveled 37.87 meters before hitting the ground.
Answer: The coefficient of friction is 0.35
Explanation:
We can write the friction force as:
F = N*μ
Where N is the normal force between the refrigerator and the ground, as the full weight of the refrigerator is acting on the ground, the normal force will be exactly equal to the weight of the refrigerator, then:
N = 650N
And μ is the coefficient of friction.
And for this case, the force is 230N, then we have:
F = N*μ
230N = 650N*μ
(230N/650N) = μ = 0.35
Notice that the distance did not matter for this calculation.