By definition, we have that the mechanical advantage is given by the following equation:
 
 Where,
 W: is the load
 T: is the tension
 Substituting the values in the given equation we have: 
 
 
 Therefore, the mechanical advantage is equal to 5.
 Answer: The mechanical advantage of this machine is: MA = 5
 
        
        
        
I need a picture plz I don’t know what to answer.
        
             
        
        
        
Parallel-plate capacitor has there fore formula is
<span>C=(<span>ϵ0</span>A)/d
putting values</span>C=(8.85*10^-12*pi*.05^2)/.00063
=1.1*10^-10F
then Q=CV=1.1*10^-10*1000=1.1*10^-7C 
as
<span>η=Q/A</span><span>therefore
(1.1*10^-7)/(pi*.05^2)
=1.4*10^-5C/m^ our answer
hope this helps</span>
        
             
        
        
        
Answer:
C = 1.01
Explanation:
Given that,
Mass, m = 75 kg
The terminal velocity of the mass, 
Area of cross section, 
We need to find the drag coefficient. At terminal velocity, the weight is balanced by the drag on the object. So,
Weight of the object = drag force
R = W
or

Where
 is the density of air = 1.225 kg/m³
 is the density of air = 1.225 kg/m³
C is drag coefficient
So,

So, the drag coefficient is 1.01.