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Serjik [45]
4 years ago
12

One degree Celsius indicates the same temperature change as

Physics
1 answer:
miss Akunina [59]4 years ago
7 0
The Celsius degree is the same size as the Kelvin.
The correct choice is 'C'.
You might be interested in
What is simple machines and it type.I need it today please​
raketka [301]

Simple machines are tools, devices or objects that are used to make work easier.

TYPES OF SIMPLE MACHINES.

  • Levers
  • Inclined Plane
  • Wedges
  • Screw
  • Pulley
  • Wheel & Axle

<u>T</u><u>H</u><u>E</u><u> </u><u>L</u><u>E</u><u>V</u><u>E</u><u>R</u><u>S</u>

A lever is simply a plank or ridge beam that is free to rotate on a pivot.

<u>P</u><u>A</u><u>R</u><u>T</u><u>S</u><u> </u><u>O</u><u>F</u><u> </u><u>A</u><u> </u><u>L</u><u>E</u><u>V</u><u>E</u><u>R</u><u> </u>

  1. Load
  2. Effort
  3. Fulcrum or pivot

<u>C</u><u>L</u><u>A</u><u>S</u><u>S</u><u>E</u><u>S</u><u> </u><u>O</u><u>F</u><u> </u><u>L</u><u>E</u><u>V</u><u>E</u><u>R</u><u>S</u>

THE FIRST CLASS LEVER

In this class, the FULCRUM is between the EFFORT and the LOAD. The mechanical advantage is more if the load is closer to the FULCRUM. Examples: seesaws, boat oars and crowbars.

THE SECOND CLASS LEVER

In this class, the LOAD is between the EFFORT and the FULCRUM. The mechanical advantage is more if the LOAD is closer to the FULCRUM. Example: wheelbarrow.

THE THIRD CLASS LEVER

In this class, the EFFORT is between the LOAD and the FULCRUM. The mechanical advantage is more if the EFFORT is closer to the LOAD. Example: garden shovel.

<u>T</u><u>H</u><u>E</u><u> </u><u>INCLINED</u><u> </u><u>PLANE</u><u> </u><u>OR</u><u> </u><u>RAMP</u>

An inclined plane is a simple machine with a sloping surface. It makes it easier for us to move objects from lower grounds to higher grounds.

<u>W</u><u>E</u><u>D</u><u>G</u><u>E</u><u>S</u>

A wedge is simply a triangular tool, often made of wood, stone, metal or plastic. It is thick at one end and tapers to a thin or sharp edge at the other end. Examples: knife, axe, doorstopper, nail, blade on the snow plough or farmer grader.

<u>PULLEY</u>

A pulley is simply a wheel with a groove in it, and a rope in the groove. It is used to lift heavy objects from the ground to high places.

<u>WHEEL</u><u> </u><u>&</u><u> </u><u>AXLE</u>

Involves two circular objects joined at the center. It works when force is applied to the wheel or when force is applied to the axle. Example: door knob.

4 0
3 years ago
One way to monitor global warming is to measure the average temperature of the ocean. Researchers are doing this by measuring th
Marat540 [252]

Answer:

0.07°C

Explanation:

<u>solution:</u>

the speed of a sound in water is<u>:</u>

v(T)=1480+4(T-4°C)

<u>at 4°C the travel time is:</u>

t(4◦C) = ( 7600 × 103 m ) / (1480 m/s) = 5202.7 s

<u>5°C, the travel time is:</u>

t(5◦C) = ( 7600 × 103 m ) / (1484 m/s) = 5188.7 s

<u>one degree C corresponds to a ∆t of 14 s so temperature difference is:</u>

ΔT=1 s/14 s=0.07◦C

5 0
3 years ago
-x times -x what is the answer​
Brilliant_brown [7]

Answer:

Explanation:

x

5 0
3 years ago
Read 2 more answers
Arrange the examples in order, starting with the object that has the least amount of energy. In each case, assume there’s no fri
Artemon [7]
First example: book, m= 0.75 kg, h=1.5 m, g= 9.8 m/s², it has only potential energy Ep,

Ep=m*g*h=0.75*9.8*1.5=11.025 J

Second example: brick, m=2.5 kg, v=10 m/s, h=4 m, it has potential energy Ep and kinetic energy Ek,

E=Ep+Ek=m*g*h + (1/2)*m*v²=98 J + 125 J= 223 J

Third example: ball, m=0.25 kg, v= 10 m/s, it has only kinetic energy Ek

Ek=(1/2)*m*v²=12.5 J.

Fourth example: stone, m=0.7 kg, h=7 m, it has only potential energy Ep,

Ep=m*g*h=0.7*9.8*7=48.02 J

The order of examples starting with the lowest energy:

1. book, 2. ball, 3. stone, 4. brick 


4 0
3 years ago
A train has a length of 81.1 m and starts from rest with a constant acceleration at time t = 0 s. At this instant, a car just re
arlik [135]

Answer: a) vcar= 7 m/s ; b) a train= 0.65 m/s^2

Explanation: By using the kinematic equation for the car and the train we can determine the above values of the car velocity and the acceletarion of the train, respectively.

We have for the car

distance = v car* t, considering the length of train (81.1 m) travel by the car during the first 11.6 s

the v car =  distance/time= 81.1 m/11.6s= 7 m/s

In order to calculate the acceleration we have to use the kinematic equation for the train from the rest

distance train = (a* t^2)/2

distance train : distance travel by the car at constant speed

so distance train= (vcar*36.35)m=421 m

the a traiin= (2* 421 m)/(36s)^2=0.65 m/s^2

4 0
3 years ago
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