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Elan Coil [88]
3 years ago
11

Hazardous wastes are placed into categories to aid in _____.

Physics
2 answers:
torisob [31]3 years ago
4 0
The waste that poses substantial or potential threats to public and environment health
Hazardous waste are actually defined as RCRA in 40 CFR 261 the the four hazardous traits are 
ignitability 
reactivity 
corrosivity  
toxicity 
i think its b
Nat2105 [25]3 years ago
4 0
The correct answer to this question is D. studying their side effects
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Which is the union of one man and one woman called?
tensa zangetsu [6.8K]
<h2>Answer: C.Monogamy </h2>

Explanation:

Monogamy is a term that refers to the sentimental and sexual bond that <u>does not allow the multiplicity of spouses. </u>

This means that love relationships are based on exclusivity, on maintaining a unique bond with your partner, refusing to develop the same kind of union or the same actions with other people.

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Question 6 of 15
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Mrs. Jones has been selected to join Space X on their next mission. When Mrs. Jones goes to
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ms jones is a good song poggers

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3 years ago
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You are riding a bicycle. If you apply a forward force of 172 N, and you and the bicycle have a combined mass of 51 kg, what wil
Natali [406]

Answer:

<h3>The answer is 3.37 m/s²</h3>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

acceleration =  \frac{force}{mass} \\

From the question

force = 172 N

mass = 51 kg

We have

acceleration  =  \frac{172}{51}  \\  = 3.372549019...

We have the final answer as

<h3>3.37 m/s²</h3>

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4 years ago
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When a body is accelerated under water, some of the surrounding water is also accelerated. This makes the body appear to have a
Alenkinab [10]

Solution :

Mass of the sphere, m = 10 kg

Diameter, D = 300 mm = 0.3 m

Volume of the sphere is $V=\frac{4}{3} \pi \left(\frac{0.3}{2}\right)^3$

                                       $V=0.01414 \ m^3$

So the volume of displaced water, $V_w=V = 0.01414 \ m^3$

Additional mass, $m_w = \frac{1}{2} \ \rho_w\times v_w$

                                  $=\frac{1}{2} \times 1000 \times 0.01414$

                                  $=7.0686 \ kg$

So the total mass, $M = m_w+m$

                                   = 7.0686 + 10

                                   = 17.0686

Force required, F = Ma

$F=17.0686 \times 10$

   = 170.686 N

4 0
3 years ago
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