Question

What is the ground-state electron configuration of the oxide ion o2−?

Answer 1

Answer : The ground-state electronic configuration of oxide ion is,

$1s^22s^22p^6$

Explanation :

Electronic configuration : It is defined as the distribution of electrons of atom in an atomic orbital.

Oxygen

The total number electrons in oxygen = 6

The electronic configuration of oxygen is,

$1s^22s^22p^4$

Oxide ion

The total number electrons in oxide ion, $O^{2-}$ = 6 + 2 = 8

The charge on O is (-2). So, we are adding 2 electrons.

The electronic configuration of oxide ion is,

$1s^22s^22p^6$