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ivanzaharov [21]
3 years ago
11

What metal is used to make hard magnets?

Physics
1 answer:
Lelu [443]3 years ago
3 0

The most common metals used for permanent magnets are iron, nickel, cobalt and some alloys of rare earth metals

You might be interested in
Stio
Ainat [17]

The true statements about magnetic fields and forces will be A,D and E.

<h3>What is a magnet?</h3>

An iron piece,alloy, or other substance with its constituent atoms arranged in such a way that it shows magnetism qualities,

The function of the magnet is attracting other iron-containing objects or aligning itself in a magnetic field.

There are two poles of the magnet;

1. North Pole.

2. South Pole.

The same poles repel each other, while the opposite poles attract each other. In a sense, south-south and north-north repel. While the north-south and the south-north attract each other.

The correct statements are;

(A). The north pole attracts the south pole of a magnet.

(D)Forces caused by magnetic fields are weaker farther from the magnet.

(E)Magnetic forces can act on an object even if the object isn't touching the magnet.

Hence, the true statements about magnetic fields and forces will be A,D and E.

To learn more about the magnet, refer to the link;

brainly.com/question/13026686

#SPJ1

3 0
2 years ago
1.10) For a fixed mass of gas at constant temperature, if the volume of the gas (V) increases to twice its original amount, the
Aliun [14]
B. 1/2p
From the relation
P1V1=P2V2
P2=P1V1/V2
If everything equals one
P2=1*1/2(1)
That would equal 1/2
I hope this helps
Please mark as brainliest
7 0
3 years ago
Read 2 more answers
Your tired 10 lb. baby cousin is cradled in your arms as you're walking back and forth across a 15m room to get her to fall asle
Mashcka [7]

Work done = Force x Distance

Force = 10 lb = 44.5 N

Work Done = 44.5 N x 15 m

= 667.5 N-m

6 0
3 years ago
Find the horizontal component and the vertical component ​
aleksandr82 [10.1K]

Answer:

v=3.66,h-3.66

Explanation:

vertical = 10sin60 - 10sin 30

horizontal =10cos60 + 10cos 30

v = 10×0.8660-10×0.5

h = 10×0.5 + 10 × 0.8660

v=8.660-5.0 = 3.66

h= 5.0-8.660 = -3.66

8 0
3 years ago
Part A If the velocity of a pitched ball has a magnitude of 47.5 m/s and the batted ball's velocity is 51.5 m/s in the opposite
nalin [4]

Explanation:

Let us assume that the mass of a pitched ball is 0.145 kg.

Initial velocity of the pitched ball, u = 47.5 m/s

Final speed of the ball, v = -51.5 m/s (in opposite direction)

We need to find the magnitude of the change in momentum of the ball and the impulse applied to it by the bat. The change in momentum of the ball is given by :

\Delta p=m(v-u)\\\\\Delta p=0.145\times ((-51.5)-47.5)\\\\\Delta p=-14.355\ kg-m/s

So, the magnitude of the change in momentum of the ball is 14.355 kg-m/s.

Let the the ball remains in contact with the bat for 2.00 ms. The impulse is given by :

J=\dfrac{\Delta p}{t}\\\\J=\dfrac{14.355}{2\times 10^{-3}}\\\\J=7177.5\ kg-m/s

Hence, this is the required solution.

7 0
3 years ago
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