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I hope you are referring to Newton's Laws of Motion by "Newton's Law".
There are three laws quoted by the great physicist of all time Sir Isaac Newton.
These laws are the building-blocks of the field of the Physics known as Classical Physics or Classical Mechanics.
Law 1. If no force applied externally, then a body in rest will always be in rest and a body in motion will continue to move in a straight line with a uniform velocity.
Law 2. The rate of change of momentum is directly proportional to the force applied and the direction of motion is always in the direction of the force applied.
Law 3. Every action has an equal and opposite reaction.
The Law 1 is also called the law of Inertia.
From the 2nd law, we can derive the equation of force, that is F =m.a (m = mass; a = acceleration)
Answer:
The axial force is ![P = 15.93 k N](https://tex.z-dn.net/?f=P%20%3D%20%2015.93%20k%20N)
Explanation:
From the question we are told that
The diameter of the shaft steel is ![d = 50mm](https://tex.z-dn.net/?f=d%20%3D%20%2050mm)
The length of the cylindrical bushing ![L =100mm](https://tex.z-dn.net/?f=L%20%3D100mm)
The outer diameter of the cylindrical bushing is ![D = 70 \ mm](https://tex.z-dn.net/?f=D%20%3D%20%2070%20%5C%20mm)
The diametral interference is ![\delta _d = 0.005 mm](https://tex.z-dn.net/?f=%5Cdelta%20_d%20%3D%200.005%20mm)
The coefficient of friction is ![\mu = 0.2](https://tex.z-dn.net/?f=%5Cmu%20%3D%200.2)
The Young modulus of steel is ![207 *10^{3} MPa (N/mm^2)](https://tex.z-dn.net/?f=207%20%2A10%5E%7B3%7D%20MPa%20%28N%2Fmm%5E2%29)
The diametral interference is mathematically represented as
![\delta_d = \frac{2 *d * P_B * D^2}{E (D^2 -d^2)}](https://tex.z-dn.net/?f=%5Cdelta_d%20%3D%20%5Cfrac%7B2%20%2Ad%20%2A%20P_B%20%2A%20D%5E2%7D%7BE%20%28D%5E2%20-d%5E2%29%7D)
Where
is the pressure (stress) on the two object held together
So making
the subject
![P_B = \frac{\delta _d E (D^2 - d^2)}{2 * d* D^2}](https://tex.z-dn.net/?f=P_B%20%3D%20%5Cfrac%7B%5Cdelta%20_d%20E%20%28D%5E2%20-%20d%5E2%29%7D%7B2%20%2A%20d%2A%20D%5E2%7D)
Substituting values
![P_B = \frac{(0.005) (207 *10^{3} ) * (70^2 - 50^2))}{2 * (50) (70) ^2 }](https://tex.z-dn.net/?f=P_B%20%3D%20%5Cfrac%7B%280.005%29%20%28207%20%2A10%5E%7B3%7D%20%29%20%2A%20%2870%5E2%20-%2050%5E2%29%29%7D%7B2%20%2A%20%2850%29%20%2870%29%20%5E2%20%7D)
![P_B = 5.069 MPa](https://tex.z-dn.net/?f=P_B%20%3D%205.069%20MPa)
Now he axial force required is
![P = \mu * P_B * A](https://tex.z-dn.net/?f=P%20%3D%20%20%5Cmu%20%2A%20P_B%20%2A%20A)
Where A is the area which is mathematically evaluated as
![\pi d l](https://tex.z-dn.net/?f=%5Cpi%20d%20l)
So ![P = \mu P_B \pi d l](https://tex.z-dn.net/?f=P%20%20%3D%20%20%5Cmu%20P_B%20%5Cpi%20d%20l)
Substituting values
![P = 0.2 * 5.069 * 3.142 * 50 * 100](https://tex.z-dn.net/?f=P%20%3D%20%200.2%20%2A%205.069%20%2A%203.142%20%2A%2050%20%2A%20100)
![P = 15.93 k N](https://tex.z-dn.net/?f=P%20%3D%20%2015.93%20k%20N)
Answer:
They will be 140 miles apart 8 hours after the first boy started the trip or 6 hours after the second boy started the trip.
Explanation:
x = the time that the first boy travels at 14 mph
x - 2 = the time the second boy travels at 14 mph
140 the distance between them
Since one travels north and the other east (their roads are perpendicular) the distance between them can be calculated using Pythagorean Theorem
(14*x)^2 + ((x-2)*14)^2 = 140^2
the solutions of the quadratic equation are
x1 = - 6 is not the solution since x > 0
x2 = 8 h is the solution
Answer:
Yes, a sled has inertia while sitting still.
Explanation:
From Newton's law of inertia, an object at rest will remain at rest unless it is acted upon by an external force. The reason the object will remain at rest unless an external force acts is because of inertia. Inertia means the resistance of an object to motion.
Thus, a sled hammer at rest will remain at rest unless it is acted upon by an external force. So we can conclude that it has Inertia.