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Otrada [13]
3 years ago
14

A car speeds up from 0 m/s to 14.0 m/s in 325 s. What is the acceleration?

Physics
1 answer:
Anton [14]3 years ago
8 0

Answer: 0.04308 m/s^2

Explanation: Plug the variables into the equation: a=\frac{v-v_{0} }{t} | v equals initial speed, v_{0} equals final speed and t equals time.

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Andrew is riding his bike is riding in a circle that has a radius of 10 m. He keeps
Dmitrij [34]

The acceleration that Andrew experience  during his ride is 3.6m/s²

The formula for calculating centripetal acceleration is expressed as:

a = v²/r

v is the speed

r is the radius

Given the following expression

v = 6m/s

r = 10m

Substitute the given parameters into the formula

a = 6²/10

a = 36/10

a = 3.6m/s²

Hence the acceleration that Andrew experience  during his ride is 3.6m/s²

Learn more here: brainly.com/question/1268866

8 0
2 years ago
A flat coil having 40 turns, each one of cross-sectional area 12.0 cm^2, is oriented with its plane perpendicular to a uniform m
iragen [17]

what means emf ? what it means

4 0
3 years ago
Which type of energy is stored in chemical compounds and released in chemical reactions?
astraxan [27]

Answer:

potential

Explanation:

4 0
3 years ago
Which of the following is not a property of displacement?
NNADVOKAT [17]

Answer:

Your correct answer is option C. Displacement is equal to the total distance traveled by an object in motion.

Explanation:

This is something that is definitely not a displacement.

4 0
3 years ago
Read 2 more answers
A bike accelerates uniformly(from rest to a speed of 7 m/s over a distance of 40 m. Determine
marshall27 [118]

Answer:

0.61 m/s^2

Explanation:

The bike's acceleration can be found by using the following suvat equation:

v^2-u^2=2as

where

v is the final velocity of the bike

u is the initial velocity

a is the acceleration

s is the distance covered

For the bike in the problem,

u = 0

v = 7 m/s

d = 40 m

Solving the equation for a, we find the acceleration:

a=\frac{v^2-u^2}{2s}=\frac{7^2-0}{2(40)}=0.61 m/s^2

3 0
3 years ago
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