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3 years ago

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A jetliner, traveling northward, is landing with a speed of 69 m/s. Once the jet touches down, it has 750 m of runway in which t

o reduce its speed to 6.1 m/s. Compute the average acceleration (magnitude and direction) of the plane during landing.

1 answer:

Katena32 [7]3 years ago

3 0

Answer:

Acceleration, $a=-3.14\ m/s^2$

Explanation:

It is given that,

Initial speed of the jetliner, u = 69 m/s

Final speed of the jetliner, v = 6.1 m/s

Distance covered, s = 750 m

We need to find the average acceleration of the jetliner. It can be calculated using third equation of motion as :

$a=\dfrac{v^2-u^2}{2s}$

$a=\dfrac{(6.1)^2-(69)^2}{2\times 750}$

$a=-3.14\ m/s^2$

So, the average acceleration of the plane during landing is $-3.14\ m/s^2$ . Hence, this is the required solution.

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