All categories

3 years ago

What influences the strength of an electric field?

Physics

2 answers:

ivolga24 [154]3 years ago

8 0

the speed of the test charge

amount of charge on the test charge

amount of charge on the source charge

location of the test charge

These are the answer choices

Ivanshal [37]3 years ago

6 0

The source/size of the charge.

The distance from the source of charge.

You might be interested in

Please help will mark Brainliest the

VLD [36.1K]

Answer: 100 units

Explanation:

4 0

2 years ago

An actor who memorizes his lines word-for-word has demonstrated _____ learning.

Nana76 [90]

<span>Mechanical association learning used by an actor to memorize his lines</span>

8 0

2 years ago

Read 2 more answers

In addition to possibly releasing harmful chemicals in the environment, mining is considered

ddd [48]

In addition to possibly releasing harmful chemicals in the environment, mining is considered B. The most dangerous job in the United States.

4 0

3 years ago

Modify how could you charge the electric circuit shown below to allow lightbulb a to stay lit even if lightbulb b is removed fro

shepuryov [24]

When a circuit is complete, or closed, electrons can flow from one end of a battery all the way around, through the wires, to the other end of the battery. Along its way, it will carry electrons to electrical objects that are connected to it – like the light bulb – and make them work!

5 0

2 years ago

f a single circular loop of wire carries a current of 45 A and produces a magnetic field at its center with a magnitude of 1.50

Lelu [443]

Answer:

Radius of the loop is 0.18 m or 18 cm

Explanation:

Given :

Current flowing through the wire, I = 45 A

Magnetic field at the center of the wire, B = 1.50 x 10⁻⁴ T

Number of turns in circular wire, N = 1

Consider R be the radius of the circular wire.

The magnetic field at the center of the current carrying circular wire is determine by the relation:

$B=\frac{N\mu_{0} I}{2R}$

Here μ₀ is vacuum permeability constant and its value is 4π x 10⁻⁷ Tm/A.

Substitute the suitable values in the above equation.

$1.50\times10^{-4} =\frac{4\pi \times10^{-7}\times45 }{2R}$

R = 0.18 m

4 0

2 years ago