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Natali [406]
3 years ago
8

) If I have 223.4 grams of iron, how many moles of iron do I have?

Chemistry
1 answer:
Natalija [7]3 years ago
3 0

Answer:

Number of moles of iron are 4 mol.

Explanation:

Given data:

Mass of iron = 223.4 g

Number of moles = ?

Solution:

Molar mass of iron = 55.85 g/mol

Formula:

Number of moles = mass/molar mass

Number of moles = 223.4 g/ 55.85 g/mol

Number of moles = 4 mol

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Why are the alloys harder than pure iron
balu736 [363]

Answer:

ok

Explanation:

Alloys are harder and stronger because the different-sized atoms of the mixed metals make the atomic layers less regular, so they cannot slide as easily.

6 0
3 years ago
What is the mass of 2.2x10^9 molecules of CO2? *​
olga55 [171]

Answer: 9.68 x 10^10 grams.

Explanation:

Given that:

Mass of CO2 = ?

Number of molecules of CO2 = 2.2x10^9 molecules

Molar mass of CO2 = ? (let unknown value be Z)

For the molar mass of CO2: Atomic mass of Carbon = 12; Oxygen = 16

= 12 + (16 x 2)

= 12 + 32 = 44g/mol

Apply the formula:

Number of molecules = (Mass of CO2 in grams/Molar mass)

2.2x10^9 molecules = Z/44g/mol

Z = 2.2x10^9 molecules x 44g/mol

Z = 9.68 x 10^10g

Thus, the mass of 2.2x10^9 molecules of CO2 is 9.68 x 10^10 grams.

4 0
3 years ago
Molecules have ionization energies, just like atoms do. The ionization energy for molecular oxygen, for example, is 1314 kJ/mol.
taurus [48]

Answer:

91.1835 nm

Explanation:

Given that the ionization energy of the oxygen molecule = 1314 kJ/mol

It means that

1 mole of oxygen molecules can be ionized by the energy = 1314 kJ = 1314000 J

1 mole of molecules contains 6.022 × 10²³ atoms

So,

6.022 × 10²³ atoms of oxygen molecules can be ionized by the energy = 1314000 J

1 atom require \frac{1314000}{6.022\times 10^{23}}\ J of energy

Energy = 2.18\times 10^{-18}\ J

Also

E=\frac {h\times c}{\lambda}

Where,  

h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

\lambda is the wavelength

So,

\lambda=\frac {h\times c}{E}

\lambda=\frac{6.626\times 10^{-34}\times 3\times 10^8}{2.18\times 10^{-18}}\ m

\lambda=91.1835\times 10^{-9}}\ m

Also,

1\ nm=10^{-9}}\ m

So, wavelength = 91.1835 nm

6 0
3 years ago
What type of reaction is illustrated?
aev [14]

Answer:

Double replacement is the answer

8 0
3 years ago
Why does bromine not react with sulphur?​
Zielflug [23.3K]

Answer:

The thermodynamic parameter which is of significance in this case is the 'Reduction Potential' for molecular bromine which is ~ +1.1 v vs N.H.E. In other words, it is a strong oxidizing agent. The bromine will oxidize sulfur compounds in which the valence of sulfur is lower than six to sulfate.

There are many possible reactions. Here is one possible example:

Na2 S2O3 + 4Br2 + 5 H2O = 2NaHSO4 + 8 HBr

8 0
3 years ago
Read 2 more answers
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