2 years ago

The reactants of two chemical equations are listed.

Chemistry

1 answer:

hjlf2 years ago

8 0

The correct answer is b

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I need to know how to do number 1. If you can please show the work so I can try to understand it. Thanks!!

Elodia [21]

Here's how you would solve it. The process should be the same for the others.

8 0

3 years ago

A 25.0 g block of a metal alloy at 100 C is dropped into an insulated flask containing 110 g of ice; 5.30 g of the ice melted. W

mr_godi [17]

Answer:

0.00353J/g/°C

Explanation:

I will assume the temperature of the ice to be approximately 0°C.

Moreover, Heat of fusion of water is 6kJ

Amount of heat used to melt 5.3g of ice = 5.3 x 6 / 18

=1.767g°C

Therefore

1.767 = 25 x specific heat cap. x 200

Specific heat cap. = 1.767/(25x200)

= 0.00353J/g/°C

6 0

3 years ago

Which characteristic cannot be inherited?

lana66690 [7]

Answer:

Knowledge of facts

Explanation:

All of these are inherited traits: Color, Height, and Shape

but Knowledge is a learnt trait

4 0

3 years ago

Read 2 more answers

What is the pH of a 0.300 M NH₃ solution that has Kb = 1.8 × 10⁻⁵ ? The equation for the dissociation of NH₃ is: NH₃ (aq) + H₂O

nalin [4]

Answer:

11.4

Explanation:

Step 1: Given data

Concentration of the base (Cb): 0.300 M

Basic dissociation constant (Kb): 1.8 × 10⁻⁵

Step 2: Write the dissociation equation

NH₃(aq) + H₂O(l) ⇄ NH₄⁺(aq) + OH⁻(aq)

Step 3: Calculate the concentration of OH⁻

We will use the following expression.

$[OH^{-} ]=\sqrt{Kb \times Cb } = \sqrt{1.8 \times 10^{-5} \times 0.300 } = 2.3 \times 10^{-3} M$

Step 4: Calculate the pOH

We will use the following expression.

$pOH =-log[OH^{-} ]= -log(2.3 \times 10^{-3} M) = 2.6$

Step 5: Calculate the pH

We will use the following expression.

$pH+pOH=14\\pH = 14-pOH = 14-2.6 = 11.4$

8 0

3 years ago

At stp what is the volume of 5.35 moles of methane ch4

Nookie1986 [14]

Answer:

22.4 L

Explanation:

8 0

2 years ago