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Eddi Din [679]
3 years ago
11

Hydrogen is used as a rocket fuel because it is very light and reacts explosively and completely with oxygen. For the combustion

reaction 2H2(g)+O2(g)⇌2H2O(g) what is the likely magnitude of the equilibrium constant K?
1. K<10−3
2. 10−3 3. K=0
4. K>103
Chemistry
1 answer:
777dan777 [17]3 years ago
7 0

Answer:

1. K<10−3

Explanation:

Equilibrium Constant is an expression which involves the concentration of the product divided by the concentration of the reactant molecules.

However the concentration of the pure liquid and pure solid is regarded as 1.

Equilibrium expression for the equation 2H2(g)+O2(g)⇌2H2O(g)

Equilibrium Constant = [H2O]^2/[H2]^2 x [O2]

Since H2O is a pure liquid, its concentration = 1

There fore;

Equilibrium Constant = 1/[H2]^2 x [O2]

This shows that the Equilibrium Constant of the equation will be less than 1 and greater than 0.

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PLS HELP ME WITN THIS ILL GIVE BRAINLIEST
pantera1 [17]

A chemical property of a substance is a certain characteristic that can only be observed by participating in a chemical reaction. Alternatively, a chemical property of a substance is something that can only be observed when the substance undergoes a chemical change.

I'm not sure what you're supposed to do with the first four boxes; all four are examples of chemical properties. Do you have to name the specific type of chemical property as given in the description? If so, the following would be my answers:

Flammability/Combustibility: The ability of a substance to burn.

The next two are quite strange; I'm not aware of a term that cleanly describes reactivity with water or acid. I suspect that, given the level of the material here, the general property of "reactivity" might be the answer for both the second and third descriptions

(Water-)reactivity: Some substances react when put in water.

(Acid-)reactivity: Some substances react when put in acid.

Light sensitivity: Light can interact with some things to form new substances.

As for the chart, I've filled it in as shown in the attached image. Please take care to double-check what I've written; in particular, when it comes to the property, I might have used a different term from what you were taught in class or provided in some other resource that I don't have access to. I've also color-coded qualitative/quantitative and physical/chemical for your convenience.

3 0
3 years ago
Give the structure of the product obtained when cyclopropene loses a proton. Will the product be aromatic or not?
astra-53 [7]

Answer:

not aromatic

Explanation:

Cyclopropene -

as the compound is is made to lose a proton , and gains a negative charge on its ring ,

Now, The ring can become aromatic or anti - aromatic depending on the number of π electrobns ,

According to Huckel 's rule ,

The cyclic compounds with ( 4n+2 ) π electrons , where , n = 0, 1, 2, 3 ... , are considered to be aromatic in nature ,

And the cyclic compounds with ( 4n ) π electrons , where , n = 1, 2, 3 ... , are considered to be anti - aromatic in nature.

Now, for the cyclopropene structure , the number of π electron are equal to 4 , 2 from the double bond and 2 from the negative charge .

Therefore , the compound becomes not aromatic or anti - aromatic .

3 0
3 years ago
The human body has four types of tissues, and the eye contains all four. Which statement correctly pairs the part of the eye
stepladder [879]

Answer:

The correct answer is D) Nerve tissue is found in the retina, the rods and cones at the back of the eye.

Explanation:

The rods and cones are photoreceptors (that is nerve cells within the eyes that can sense light) which is situated in the retina.

These photoreceptors also sense colours and send these signals into the optic nerve for transmission to the brain.

Cheers

6 0
3 years ago
Last question, I promise!!!!!! ... :&gt;
VikaD [51]

Answer:

Which question?

Explanation:

3 0
3 years ago
Read 2 more answers
The following reactions take place in the ozone layer by the absorption of ultraviolet light.
____ [38]

Answer:

Option B will require a shorter wave length of light.

Explanation:

The bonding between Ozone (O3) and Oxygen (O2) can be used to explain why the breaking of oxygen into Oxygen radicals will require a shorter wave length.

  • The bond between Oxygen (O2) is a double bond while Ozone (O3) has an intermediate bond between a double bond and a single bond.
  • The bond order of Oxygen (O2) is equals 2 while that of Ozone (O3) is 1.5. Since the bond order of oxygen is higher, it will require more energy to break the bond compared to breaking the Ozone (O3) bond.
  • Recall that Energy is inversely proportional to wave length.
  • So it will require a shorter wave length to break the Oxygen (O2) into its radicals.
5 0
3 years ago
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