Answer:
12 mol O2
Explanation:
This is assuming you're using a combustion equation of
2 H2S + 3O2 -> 2H2O + 2SO2
Next time include the equation because that is where you will find your mol to mol ratio
8 mol H2S x (3 mol O2 / 2 mol H2S) = 12 mol O2
B because ice water is water which molocules move fast like air
Answer:
SO₄²⁻(aq) +Sn²⁺(aq) +4H⁺ → H₂SO₃(aq) + Sn⁴⁺(aq) + H₂O
Explanation:
At first calculate the oxidation state of that element which undergoes oxidation as well as reduction.
for SO₄²⁻ the oxidation state of sulphur is +6 and H₂SO₃ the oxidation state of sulphur is +4
So balance equation is
(Reduction) SO₄²⁻ + 4H⁺+ 2e⁻ → H₂SO₃ + H₂O.........................................(1)
(oxidation) Sn²⁺ → Sn⁴⁺ + 2e⁻ .............................................................(2)
Adding equation 1 & 2
we get
SO₄²⁻(aq) +Sn²⁺(aq) +4H⁺ → H₂SO₃(aq) + Sn⁴⁺(aq) + H₂O
Answer:
Conocer el número de oxidación de los elementos de un compuesto es de vital importancia para conocer si una semirreacción es de oxidación o de reducción en las reacciones de ese tipo.