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Eddi Din [679]
2 years ago
11

Hydrogen is used as a rocket fuel because it is very light and reacts explosively and completely with oxygen. For the combustion

reaction 2H2(g)+O2(g)⇌2H2O(g) what is the likely magnitude of the equilibrium constant K?
1. K<10−3
2. 10−3 3. K=0
4. K>103
Chemistry
1 answer:
777dan777 [17]2 years ago
7 0

Answer:

1. K<10−3

Explanation:

Equilibrium Constant is an expression which involves the concentration of the product divided by the concentration of the reactant molecules.

However the concentration of the pure liquid and pure solid is regarded as 1.

Equilibrium expression for the equation 2H2(g)+O2(g)⇌2H2O(g)

Equilibrium Constant = [H2O]^2/[H2]^2 x [O2]

Since H2O is a pure liquid, its concentration = 1

There fore;

Equilibrium Constant = 1/[H2]^2 x [O2]

This shows that the Equilibrium Constant of the equation will be less than 1 and greater than 0.

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Answer:

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Light shining on a strip of metal can dislodge electrons. Do you think this is more consistent with light being made up of waves
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A 1.897g sample of Mg(HCO3)2 was heated and decomposed. When the sample
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1.5 % is the percent yield in the reaction.

Explanation:

Given that:

original mass of the sample used in reaction = 1.897 grams

product formed after decomposition = 1.071 grams

The reaction for the decomposition:

Mg(HCO3)2 (s) ⇒ CO2 (g) + H2O (g) + MgCO2 (s)

It says that 1 mole of Mg(HCO3)2  yielded 1 mole of  MgCO2  on decomposition

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percent yield = \frac{actual yield}{theoretical yield} x 100

putting the values in the equation:

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