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Eddi Din [679]
3 years ago
11

Hydrogen is used as a rocket fuel because it is very light and reacts explosively and completely with oxygen. For the combustion

reaction 2H2(g)+O2(g)⇌2H2O(g) what is the likely magnitude of the equilibrium constant K?
1. K<10−3
2. 10−3 3. K=0
4. K>103
Chemistry
1 answer:
777dan777 [17]3 years ago
7 0

Answer:

1. K<10−3

Explanation:

Equilibrium Constant is an expression which involves the concentration of the product divided by the concentration of the reactant molecules.

However the concentration of the pure liquid and pure solid is regarded as 1.

Equilibrium expression for the equation 2H2(g)+O2(g)⇌2H2O(g)

Equilibrium Constant = [H2O]^2/[H2]^2 x [O2]

Since H2O is a pure liquid, its concentration = 1

There fore;

Equilibrium Constant = 1/[H2]^2 x [O2]

This shows that the Equilibrium Constant of the equation will be less than 1 and greater than 0.

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In the titration of 50. 0 mL of 0. 400 M HCOOH with 0. 150 M LiOH, how many mL of LiOH are required to reach the equivalence poi
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The volume of the 0.15 M LiOH solution required to react with 50 mL of 0.4 M HCOOH to the equivalence point is 133.3 mL

<h3>Balanced equation </h3>

HCOOH + LiOH —> HCOOLi + H₂O

From the balanced equation above,

The mole ratio of the acid, HCOOH (nA) = 1

The mole ratio of the base, LiOH (nB) = 1

<h3>How to determine the volume of LiOH </h3>
  • Molarity of acid, HCOOH (Ma) = 0.4 M
  • Volume of acid, HCOOH (Va) = 50 mL
  • Molarity of base, LiOH (Mb) = 0.15 M
  • Volume of base, LiOH (Vb) =?

MaVa / MbVb = nA / nB

(0.4 × 50) / (0.15 × Vb) = 1

20 / (0.15 × Vb) = 1

Cross multiply

0.15 × Vb = 20

Divide both side by 0.15

Vb = 20 / 0.15

Vb = 133.3 mL

Thus, the volume of the LiOH solution needed is 133.3 mL

Learn more about titration:

brainly.com/question/14356286

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