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mylen [45]
3 years ago
12

261 nm to millimeters

Chemistry
1 answer:
Komok [63]3 years ago
5 0
The answer is <span>0.000261 millimeters</span>
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What is the mass of silver in 4.3g AgNO3?
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4.22 grams.
1. First find out how much AgNO3 weighs with one mole (107.87 g Ag + 14.007 g N + 48 g O = 169.89 grams)
2. Find the percent of Ag you have. So, (107.87 g/mol Ag)/(169.89 g/mol AgNO3)= 0.63 * 100 = 63%.
3. If you have 6.7 grams total, you know 63% of it is going to be silver, so just multiply 6.7 grams by .63 and you get 4.22 g Ag
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If you filter a mixture of sand and salt-water, what will the solid residue in the filter paper consist of?
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Does an acid gain or lose a hydrogen cation, H+, during an acid-base reaction?
elena-s [515]

It loses an H+.

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In the reaction: C6H6 + O2 = CO2 + H2O If 26.2 grams of C6H6 is reacted in a 0.250-liter container and this reaction is carried
Lelechka [254]
<h3>Answer:</h3>

43.33 atm

<h3>Explanation:</h3>

We are given;

Mass of C₆H₆ = 26.2 g

Volume of the container = 0.25 L

Temperature = 395 K

We are required to calculate the pressure inside the container;

First, we calculate the number of moles of C₆H₆

Molar mass of C₆H₆ =  78.1118 g/mol.

But; Moles = mass ÷ Molar mass

Moles of  C₆H₆ = 26.2 g ÷  78.1118 g/mol.

                         = 0.335 moles C₆H₆

Second, we calculate the pressure, using the ideal gas equation;

Using the ideal gas equation, PV = nRT , Where R is the ideal gas constant, 0.082057 L.atm/mol.K

Therefore;

P = nRT ÷ V

  = (0.335 mol × 0.082057 × 395 K) ÷ 0.25 L

 = 43.433 atm

Therefore, the pressure inside the container is 43.33 atm

6 0
3 years ago
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