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Ber [7]
4 years ago
10

In 1970, a rocket powered car called Blue Flame achieved a maximum speed of 1.00(10 km/h (278m/s).Suppose the magnitude of the c

ar's constant acceleration is 5.56 m/s^2. If the car is initially at rest , what is the distance traveled. During its acceleration?
Physics
1 answer:
sammy [17]4 years ago
3 0

Answer:

Distance traveled during this acceleration will be 6950 m

Explanation:

Wear have given maximum speed tat will be equal to final speed of the car        v = 278 m/sec

Constant acceleration a=5.56m/sec^2

As the car starts initially starts from rest so initial velocity of the car u = 0 m/sec

From third equation of motion v^2=u^2+2as

Putting all values in equation

278^2=0^2+2\times 5.56\times s

s = 6950 m

So distance traveled during this acceleration will be 6950 m

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defon

Answer:

11.11 C

Explanation:

(52 f-32) * 5/9= 11.11

7 0
3 years ago
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Determine the number of atoms per unit cell in a (a) face-centered cubic, (b) body- centered cubic, and (c) diamond lattice.
fredd [130]

Answer:

a) 4

b) 2

c) 8

Explanation:

In a cubic lattice, each atom of the vertex is shared among other 8 unit cells, so the atoms on the vertex contribute to 1/8 to a given unit cell.

a) Ina face-centered cubic we have 8 atoms on the vertex and one in each face, which is shared with another unit cell, so it contribute to 1/2

Therefore, the total atoms are:

8*(1/8) + 6*(1/2) = 4

b) In the body centered cubic structure, the centered atom is not shared with another cell, therefore it contribute to 1 to the given cell:

The number of atoms per unit cel is:

8*(1/8) + 1 = 2

c) The diamond lattice is similar to the face-centered cubic lattice but it contains two identical atoms per lattice point.

Therefore it must contain twice atoms than the face-centered cubic lattice:

that is, it has 8 atoms per unit cell

3 0
4 years ago
An object experiences an acceleration of 6.8m/s2.As a result,it accelerates from rest to 24m/s.How much distance did it travel d
Hitman42 [59]

The distance covered by the object is 42.4 m

Explanation:

The motion of the object is a uniformly accelerated motion (at constant acceleration), therefore we can use the following suvat equation:

v^2 -u^2 = 2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance covered

For the object in this problem, we have:

u = 0 (it starts from rest)

v = 24 m/s (final velocity)

a=6.8 m/s^2

Solving for s, we find the distance travelled by the object:

s=\frac{v^2-u^2}{2a}=\frac{24^2-0}{2(6.8)}=42.4 m

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

8 0
3 years ago
Suppose that an object is moving with constant nonzero acceleration. Which of the following is an accurate statement concerning
Wittaler [7]

Answer: The right answer is b)

Explanation:

By definition, acceleration is the change in velocity (in module or direction) over a given time interval, as follows:

a = (v-v₀) / (t-t₀)

If we take t₀ = 0 (this is completely arbitrary), we can rewrite the equation above, as follows:

v = v₀ + at

We can recognize this function as a linear one, where a represents the slope of the line.

If a is constant, this means that the relationship between the change in velocity and the change in time remains constant, in other words, in equal times, its velocity changes in an equal amount.

Let's suppose that a = 10 m/s/s. (Usually written as 10 m/s²).

This is telling us that each second, the velocity increases 10 m/s.

8 0
3 years ago
Two beams of coherent light travel different paths, arriving at point P. If the maximum destructive interference is to occur at
Nimfa-mama [501]

Answer:

The path difference between the two waves should be one-half of a wavelength

Explanation:

When two beams of coherent light travel different paths, arriving at point P. If the maximum destructive interference is to occur at point P , then the condition for it is that the path difference of two beams must be odd multiple of half wavelength. Symbolically

path difference = ( 2n+1 ) λ / 2

So path difference may be λ/2 , 3λ/ 2,  5λ/ 2 etc .

Hence right option is

The path difference between the two waves should be one-half of a wavelength.

5 0
3 years ago
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