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2 years ago

Write down the relation between energy and power

Physics

2 answers:

gizmo_the_mogwai [7]2 years ago

6 0

Answer:

Energy is what makes change happen and can be transferred form one object to another. Energy can also be transformed from one form to another. Power is the rate at which energy is transferred. It is not energy but is often confused with energy.

Explanation:

Nookie1986 [14]2 years ago

3 0

Answer:

when u have energy u will have power n u can work as power is the capacity to do the work

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Calculate the ratio of the resistance of 12.0 m of aluminum wire 2.5 mm in diameter, to 30.0 m of copper wire 1.6 mm in diameter

alukav5142 [94]

Answer: 0.258

Explanation:

The resistance $R$ of a wire is calculated by the following formula:

$R=\rho\frac{l}{s}$ (1)

Where:

$\rho$ is the resistivity of the material the wire is made of. For aluminium is $\rho_{Al}=2.65(10)^{-8}m\Omega$ and for copper is $\rho_{Cu}=1.68(10)^{-8}m\Omega$

$l$ is the length of the wire, which in the case of aluminium is $l_{Al}=12m$ , and in the case of copper is $l_{Cu}=30m$

$s$ is the transversal area of the wire. In this case is a circumference for both wires, so we will use the formula of the area of the circumference:

$s=\pi{(\frac{d}{2})}^{2}$ (2) Where $d$ is the diameter of the circumference.

For aluminium wire the diameter is $d_{Al}=2.5mm=0.0025m$ and for copper is $d_{Cu}=1.6mm=0.0016m$

So, in this problem we have two transversal areas:

For aluminium:

$s_{Al}=\pi{(\frac{d_{AL}}{2})}^{2}=\pi{(\frac{0.0025m}{2})}^{2}$

$s_{Al}=0.000004908m^{2}$ (3)

For copper:

$s_{Cu}=\pi{\frac{(d_{Cu}}{2})}^{2}=\pi{(\frac{0.0016m}{2})}^{2}$

$s_{Cu}=0.00000201m^{2}$ (4)

Now we have to calculate the resistance for each wire:

Aluminium wire:

$R_{Al}=2.65(10)^{-8}m\Omega\frac{12m}{0.000004908m^{2}}$ (5)

$R_{Al}=0.0647\Omega$ (6) Resistance of aluminium wire

Copper wire:

$R_{Cu}=1.68(10)^{-8}m\Omega\frac{30m}{0.00000201m^{2}}$ (6)

$R_{Cu}=0.250\Omega$ (7) Resistance of copper wire

At this point we are able to calculate the ratio of the resistance of both wires:

$Ratio=\frac{R_{Al}}{R_{Cu}}$ (8)

$\frac{R_{Al}}{R_{Cu}}=\frac{0.0647\Omega}{0.250\Omega}$ (9)

Finally:

$\frac{R_{Al}}{R_{Cu}}=0.258$ This is the ratio

3 0

3 years ago

Photons of wavelength 65.0 pm are Compton-scattered from a free electron which picks up a kinetic energy of 0.75 keV from the co

DIA [1.3K]

0.6764*10^-10m

Explanation:

Using E= hc/wavelength

(4.14x10^-15)x(3.0x10^8)/(65x10^-12)=0.1911x10^5 eV=19.1 keV

So subtract the calculated energy from the given energy of scattered photons

9.11-0.75=18.36 keV

To find wavelength

Wavelength= hc/ E

[(4.14x 10^-15)x (3.0x10^8)]/(18.36*10^3) =0.6764^-10 m

8 0

3 years ago

A hiker walks 200 m west and then walks 100 m north. In what direction is her resulting displacement?a. northb. westc. northwest

emmainna [20.7K]

Answer:

Option (C) is correct.

Explanation:

Assuming that the hiker starts walking from the origin O as shown in the figure.

First, he walks 200 m west to point A (say), then he walks 100 m north to the final point B (say) as shown in the figure.

The final point B is in the north-west direction, therefore, the resulting point is in the north-west direction.

Hence, option (C) is correct.

7 0

2 years ago

An object moves with constant velocity . •1st law •2nd law

denis23 [38]

Answer:

An object moves with constant velocity .

Explanation:

•2nd law

4 0

2 years ago

Radio waves are the only type of electromagnetic wave that is a transverse wave.

Pavlova-9 [17]

Answer:

false

Explanation:

7 0

2 years ago

Write down the relation between energy and power​

Write down the relation between energy and power