Let x mph be the speed of the ship in still water.
Against the current, the net speed is, (x-1.9) mph.
Time, t= distance, d/ Speed, v => 9= 113.4/(x-1.9) => 9(x-1.9) = 113.4 => x-1.9 = 113.4/9 => x = 12.6+1.9 = 14.5 mph
Moving with the current, the net speed of the ship = 14.5+1.9 =16.4 mph
Time take, t = d/v = 113.4/16.4 = 6.915 hours
That statement is flase. The index of refraction
of every material is more than 1.0 .
Answer: In the 5th dimension, they who claim to know, say that there is only one time, including the past and the future.
Answer:
volume : {l}^3
speed: (l)^1*(t)^-1
Explanation:
Volume is a measure of 3 dimensional space. It is expressed with 3 orthogonal lengths. The volume of a box would be the product of it's height, width and length. These 3 are longitudes that can be expressed in meters, feet, inches, etc. Because these are 3 longitudes multiplied the result will be a cubic longitude (l)^3.
A more general method for finding a volume is to use integral calculus:
This is for Cartesian coordinates. Cylindrical and spherical coordinates can also be used.
Speed is defined as the rate of change in position respect of time:
For movement in one dimension.
For movement in 3 dimensions you calculate the speed component of each space direction and express them as components of a speed vector:
This is a vector of velocity components, each one is expressed as a division of a longitude over a time, so speed components have dimensions of (l)^1*(t)^-1
The speed vector has a magnitude that is obtained with the Pitagoras theorem:
Since each component is squared, added together and then the square root is taken this magnitude is also in (l)^1*(t)^-1
Answer:
Explanation:
We shall represent the velocity of cruise ship and coast guard petrol boat in vector form .
velocity of cruise ship
Vcs = - 2.5 j
Vpb = - 4.8 cos 19 i + 4.8 sin 19 j = - 4.54 i + 1.56 j
velocity of the cruise ship relative to the patrol boat
= Vcs - Vpb
= - 2.5 j - ( - 4.54 i + 1.56 j )
= - 2.5 j + 4.54 i - 1.56 j
= 2.04 i - 1.56 j .
x-component of the velocity of the cruise ship relative to the patrol boat
= 2.04 m /s
y-component of the velocity of the cruise ship relative to the patrol boat
= - 1.56 m /s .