Answer:
A) 29.4 m 17.0 m; B) 2 m
Explanation:
If a vector is 34.0 m in length and is directed 60.0° east of north (which means 30.0° over the horizontal), then its coordinates will be:
Horizontal: (34.0 m)cos(30.0°)=29.4 m
Vertical: (34.0 m)sin(30.0°)=17 m
If one person walks 8.0 meters in a straight line and then walks 5.0 meters in another straight line, then the minimum displacement would be to go back over his tracks, displacing himself 8m-5m=3m, while the maximum displacement would be going straight ahead, displacing himself 8m+5m=13m. Any answer outside this interval is impossible (2m).
Answer:
The acceleration of a 2 kg box acted on by a net force of 2 N is solved by using Newton’s second law of motion in the form acceleration = F_net / mass. Since the mass of the box is 2 kg and the net force is 2 N, the acceleration of the 2 kg box is 1 m/s^2.
Speed is defined as the distance over time. So in measuring the speed of a car, the most manual thing that we can do besides using a speedometer is to measure a certain distance then measure the time at which the car passes that distance then divide the distance over the time. Then determine the speed limit.
Answer:
770.1 m
Explanation:
From the question given above, the following data were obtained:
Velocity (v) = 45.3 m/s
Time (t) = 17 s
Displacement (d) =?
Velocity is defined according to the following formula:
Velocity = Displacement /Time
With the above formula, we can obtain the displacement of the ball as follow:
Velocity = Displacement /Time
45.3 = Displacement / 17
Cross multiply
Displacement = 45.3 × 17
Displacement = 770.1 m
Therefore the displacement of the ball is 770.1 m
Work force distance formula is <span>W = Fscosθ.
</span>The answer is 271.89 I believe.