Answer:
15.2 m/s²
Explanation:
Acceleration: This can be defined as the rate of change of velocity. The S.I unit of acceleration is m/s²
From the question,
F-W = ma......................... Equation 1
Where F = Tension on the line, W = weight of the fish, m = mass of the fish, a = acceleration of the fish.
But,
W = mg........................ Equation 2
Where g = acceleration due to gravity.
Substitute equation 2 into equation 1
F-mg = ma
make a the subject of the equation
a = (F-mg)/m.................... Equation 3
Given: F = 150 N, m = 6 kg,
Constant: g = 9.8 m/s²
Substitute into equation 2
a = [150-(6×9.8)]/6
a = (150-58.8)/6
a = 91.2/6
a = 15.2 m/s²
Hence the minimum acceleration of the fish = 15.2 m/s²
I believe the answer is conduction.
<span>The ball clears by 11.79 meters
Let's first determine the horizontal and vertical velocities of the ball.
h = cos(50.0)*23.4 m/s = 0.642788 * 23.4 m/s = 15.04 m/s
v = sin(50.0)*23.4 m/s = 0.766044 * 23.4 m/s = 17.93 m/s
Now determine how many seconds it will take for the ball to get to the goal.
t = 36.0 m / 15.04 m/s = 2.394 s
The height the ball will be at time T is
h = vT - 1/2 A T^2
where
h = height of ball
v = initial vertical velocity
T = time
A = acceleration due to gravity
So plugging into the formula the known values
h = vT - 1/2 A T^2
h = 17.93 m/s * 2.394 s - 1/2 9.8 m/s^2 (2.394 s)^2
h = 42.92 m - 4.9 m/s^2 * 5.731 s^2
h = 42.92 m - 28.0819 m
h = 14.84 m
Since 14.84 m is well above the crossbar's height of 3.05 m, the ball clears. It clears by 14.84 - 3.05 = 11.79 m</span>
Well water would prob be your best bet, you could extract the salt first and then use a magnet to seperate the iron filing from the sand
Answer:
a = - 0.3376 g's
Explanation:
The sports car has a constant speed when travelling. Covered 164 m in 13.77 s. Thus, speed = 164/13.77 m/s
It brakes and now comes to a stop in 3.6 s.
Thus final velocity = 0 m/s
Formula for acceleration is;
a = (v - u)/t
a = (0 - (164/13.77))/3.6
a = -3.308 m/s²
In terms of g's", where 1.00 g = 9.80 m/s², we have;
a = -3.308/9.8 g's
a = - 0.3376 g's
