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mojhsa [17]
3 years ago
12

Under what conditions will light bend?

Physics
2 answers:
Rudiy273 years ago
4 0
Light will not bend under any conditions.  It always proceeds straight
along its path.

The path can bend ... either abruptly, at an interface between two
media with different refractive indices, or continuously, when the
index of refraction changes along a line perpendicular to the path
(as it does in the Earth's atmosphere).  
pochemuha3 years ago
3 0
Light CAN in fact bend, but maybe not on Earth. At least as far as I know. Near a black hole, where gravitational force is so strong that even light is sucked, light is bent do
Ue to the gravitational force. This is how astronomers find and identify black holes.
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.A coin rolls off the edge of a table. The coin
geniusboy [140]

Answer:

Apply the following formulae horizontally And get A value for time

Remember horizontal acceleration is zero

s  = ut +  \frac{1}{2}a {t}^{2}   \\ 0.8 = 1.7 \times t \\  \frac{0.8}{1.7}  = t \\ t = 0.47s

and then to find the height apply the same above equation vertically...remember vertical initial velocity is zero

s = ut +  \frac{1}{2} a {t}^{2}  \\ s =  \frac{1}{2}  \times 10 \times (0.47) ^{2}  \\ s = 1.1045m

5 0
3 years ago
Which of the outer planets would you most likely visit? Why? What would you see on your visit?
Tanzania [10]
I would like to visit Pluto because i want to see what a Dwarf planet would look like, i would like to see what kind of minerals are in the planet its self..


Brainliest answer?

6 0
3 years ago
Read 2 more answers
The latitude of the city of Arlington is about 32.7357°. Calculate the following: (a) The angular speed of the Earth. (b) The li
julia-pushkina [17]

Answer:

Explanation:

a ) The earth rotates by 2π radian in 24 x 60 x 60 s

so angular speed ( w )  = 2π / (24 x 60 x 60)  = 7.268 x  10⁻⁵ rad / s

b ) Linear speed of city of Arlington ( v )  = w r = w R Cosλ where R is radius of the earth and λ is latitude .

v = 7.268 x 10⁻⁵ x  6.371 x 10⁶ cos 32.7357

389.5 m /s

acceleration = w² r = w² R Cos 32.7357

= (7.268 x 10⁻⁵ )² x 6.371 x 10⁶ x cos 32.7357

=283.08 x 10⁻⁴ m/s²

c) velocity ratio =

w r /w R =

R cos 32.73/ R  

= Cos 32.73

= 0.84 .

6 0
3 years ago
A meteoroid is moving towards a planet. It has mass m = 0.78×109 kg and speed v1 = 4.1×107 m/s at distance R1 = 2.8×107 m from t
wariber [46]

Answer:

PE=81.755\, J

Explanation:

Given that:

  • mass of meteoroid, m=7.8\times 10^8 \,kg
  • radial distance from the center of the planet, R= 2.8\times 10^7 m
  • mass of the planet, M=4.4\times 10^{25}\, kg

<u>For gravitational potential energy we have:</u>

PE=G\frac{M.m}{R}

substituting the respective values:

PE=6.67\times 10^{-11}\times \frac{4.4\times 10^{25}\times 7.8\times 10^8}{2.8\times 10^7}

PE=81.755\, J

5 0
3 years ago
Which of these are terrestrial planets? Select all that apply.
Strike441 [17]
The answers to the question above would be letters a, b, c, and d. The terrestrial planets are those that are close to the sun, namely, Mercury, Venus, Earth, and Mars. The others are known as the gas giants since they have a thick atmosphere and are considerably cold.
5 0
4 years ago
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