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3 years ago

A 3.2 kg ball that is moving straight upward has 17 Joules of kinetic energy. The total mechanical energy is 25 Joules.

Physics

1 answer:

bija089 [108]3 years ago

7 0

Answer:

h = 0.25 [m]

v = 3.26 [m/s]

Explanation:

In order to solve this problem, we must remember that mechanical energy is defined as the sum of kinetic energy plus potential energy.

E1 = Ek + Ep

where:

E1 = mechanical energy = 25 [J]

Ek = kinetic energy = 17 [J]

Ep = potential energy [J]

25 = 17 + Ep

Ep = 8 [J]

Now the potential energy is defined by the following equation:

Ep = m*g*h

where:

m = mass = 3.2 [kg]

g = gravity acceleration = 9.81 [m/s²]

h = elevation [m]

8 = 3.2*9.81*h

h = 0.25 [m]

The velocity can be calculated by means of kinetic energy.

$E_{k} =\frac{1}{2} *m*v^{2}\\17 =\frac{1}{2} *3.2*v^{2} \\v= \sqrt{\frac{17*2}{3.2} }\\v = 3.26[m/s]$

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Label the different parts of a heart:

Reptile [31]

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4 years ago

Yosef is playing with different kinds of rubber bands. Some are very narrow and some are quite wide. Yosef is curious about the

kari74 [83]

Answer:

He could have many different hypothesis, but here is one.

Explanation:

If rubber bands are wider, then the rubber bands will stretch further, because the wider a rubber band is the stronger it is.

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3 years ago

Read 2 more answers

The potential energy between two atoms in a particular molecule has the form U(x) = 2.1 x 8 − 5.2 x4 where the units of x are le

a_sh-v [17]

Answer:

$x\approx 0.948$

Explanation:

The correct formula for the potential energy between two atoms in a particular molecule is:

$U(x) = \frac{2.1}{x^{8}}-\frac{5.2}{x^{4}}$

Where $x$ is the distance.

According to the definitions of potential energy and work, as well as the Work-Energy Theorem and the Principle of Energy Conservation. The relation between that and related force is:

$F = -\frac{dU}{dx}$

The function is derived in terms of distance:

$F (x) = \frac{84}{5\cdot x^{9}} -\frac{104}{5\cdot x^{5}}$

Then, it is needed to find at least of x so that F(x) equals to 0.

$\frac{84}{5\cdot x^{9}}-\frac{104}{5\cdot x^{5}}=0$

$\frac{84}{x^{4}}-104 = 0$

$84-104\cdot x^{4} = 0$

$x=\sqrt[4]{\frac{84}{104} }$

$x\approx 0.948$

7 0

3 years ago

Determine the kinetic energy of a 1000-kg roller coaster car that is moving with a speed of 20.0 m/s.

ankoles [38]

Answer:

The correct answer is - 200000 J

Explanation:

We use the formula of kinetic energy:

The formula to calculate kinetic energy is,

Here,

Ec =1/2 x m x v^2

The mass of the roller coaster is, m = 1000 k g

The speed of the roller coaster is, v = 20.0 m/s

Therefore,

Ec=1/2 x 1000kg x (20m/s)^2 = 200.000Joule

200,000J

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3 years ago

What is the time constant of a series circuit where the capacitor is 0.330μF and the resistor is 10Ω ?

PtichkaEL [24]

Answer:

$\tau=3.3*10^{-6}s$

Explanation:

Take at look to the picture I attached you, using Kirchhoff's current law we get:

$C*\frac{dV}{dt}+\frac{V}{R}=0$

This is a separable first order differential equation, let's solve it step by step:

Express the equation this way:

$\frac{dV}{V}=-\frac{1}{RC}dt$

integrate both sides, the left side will be integrated from an initial voltage v to a final voltage V, and the right side from an initial time 0 to a final time t:

$\int\limits^V_v {\frac{dV}{V} } =-\int\limits^t_0 {\frac{1}{RC} } \, dt$

Evaluating the integrals:

$ln(\frac{V}{v})=e^{\frac{-t}{RC} }$

natural logarithm to both sides in order to isolate V:

$V(t)=ve^{-\frac{t}{RC} }$

Where the term RC is called time constant and is given by:

$\tau=R*C=10*(0.330*10^{-6})=3.3*10^{-6}s$

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3 years ago