Answer:
Lower than it should be.
Explanation:
Hello.
In this case, since the density is computed by:
![\rho =\frac{m}{V}](https://tex.z-dn.net/?f=%5Crho%20%3D%5Cfrac%7Bm%7D%7BV%7D)
And we obtain the volume of the solid by substracting the mass of the water and the solid minus the mass of water:
![V_{solid}=V_{solid\ with \ water}-V_{water}](https://tex.z-dn.net/?f=V_%7Bsolid%7D%3DV_%7Bsolid%5C%20with%20%5C%20water%7D-V_%7Bwater%7D)
If some water is splashed out of the cylinder, the volume of water will be lower than originally measured, it means that the volume of the solid will be higher than real. In such a way, since the density is in an inversely proportional relationship with volume, as the volume of the solid is wrongly increased, therefore the density of the solid will be lower than in should be.
Regards.
4. a poor insulator
If rest other things are kept constant or unchanged then a good conductor can be termed as a poor insulator.
Answer:
64 kPa
Explanation:
The pressure exerted by a force on a surface is given by
![p=\frac{F}{A}](https://tex.z-dn.net/?f=p%3D%5Cfrac%7BF%7D%7BA%7D)
where
p is the pressure
F is the force
A is the area on which the force is exerted
In this problem, let's call:
F = the weight of the performer, which is the force
A = the area of 1 stilt
At the beginning, the performer is standing on both stilts, so the area on which he exerts pressure is 2A. So the pressure is
(1)
Later, he stands on one stilt only. The force exerted is still the same (his weight), however, the area is now reduced to A; therefore, the new pressure is
![p'=\frac{F}{A} = 2(\frac{F}{2A})=2p](https://tex.z-dn.net/?f=p%27%3D%5Cfrac%7BF%7D%7BA%7D%20%3D%202%28%5Cfrac%7BF%7D%7B2A%7D%29%3D2p)
which is twice the value calculated in (1); so, the new pressure is
![p'=2(32)=64 kPa](https://tex.z-dn.net/?f=p%27%3D2%2832%29%3D64%20kPa)
Answer:
professional communication style is expected to be formal while the casual is informal.
Explanation: