Answer: The vapor pressure of a mixture of 80 g of ethanol and 97 g of methanol at 293 K is 78.3 torr.
Explanation:
According to Raoult's law, the vapor pressure of a component at a given temperature is equal to the mole fraction of that component multiplied by the vapor pressure of that component in the pure state.
and 
where, x = mole fraction in solution
= pressure in the pure state
According to Dalton's law, the total pressure is the sum of individual pressures.
moles of ethanol=
moles of methanol= 
Total moles = moles of ethanol + moles of methanol = 1.7 +3.0 = 4.7
Thus the vapor pressure of a mixture of 80 g of ethanol and 97 g of methanol at 293 K is 78.3 torr.
- 3.5
- 9
- 24.7
- 8.01
- 0.006
- 13(1.25×1012=12.65)
Explanation:
Above we have simply looked the condition that where we put decimal point that gives your needed answer after round off.
For example:
we have to make 2 s.f from 345 so we kept decimal after 3 and we rounded off to make 3.5 from 3.45
Hope you got it
Answer: 20 mg Te-99 remains after 12 hours.
Explanation: N(t) = N(0)*(1/2)^(t/t1/2)
N(t) = (80 mg)*(0.5)^(12/6)
N(t) = 20 mg remains after 12 hours
Answer:
NaNO3
Explanation:
When you're dealing with the rules of solubility (Which compounds dissolve in water), there's a set of numbered rules you can follow. You can find them in your textbook, but here's a short cut:
ANY, ANY, ANY compound that contains any of the following is soluble in water no mater what!
Na, NO3, NH4, K, ClO4, CH3COO
If you see sodium, nitrate, ammonium, perchlorate or acetate in the compound, it is soluble in water...
