........................................................................................
Answer:
t = 8.45 sec
car distance d = 132.09 m
bike distance d = 157.08 m
Explanation:
GIVEN :
motorcycle is 25 m behind the car , therefore distance need to covered by bike to overtake car is 25+ d, when car reache distance d at time t
for car
by equation of motion

u = 0 starting from rest


for bike


equating time of both

solving for d we get
d = 132 m
therefore t is

t = 8.45 sec
each travelled in time 8.45 sec as
for car

d = 132.09 m
fro bike

d = 157.08 m
A) its 's hazardous for hundreds to thousand of year B) Some waste can be recycled and used again is the answer
<span>32 mph
First, let's calculate the location of the particle at t=1, and t=4
t=1
s = 6*t^2 + 2*t
s = 6*1^2 + 2*1
s = 6 + 2
s = 8
t = 4
s = 6*t^2 + 2*t
s = 6*4^2 + 2*4
s = 6*16 + 8
s = 96 + 8
s = 104
So the particle moved from 8 to 104 over the time period of 1 to 4 hours. And the average velocity is simply the distance moved over the time spent. So:
avg_vel = (104-8)/(4-1) = 96/3 = 32
And since the units were miles and hours, that means that the average speed of the particle over the interval [1,4] was 32 miles/hour, or 32 mph.</span>
Answer
Force will be 1520.2604 N
Explanation:
We have given mass of the bullet m = 10.1 gram = 0.0101 kg
Distance S= 0.6 m
Final velocity v = 425 m/sec
Initial velocity u will be 0 m/sec
From third equation of motion 


We know that force is given by F = ma
So force = 0.0101×150520.833 = 1520.2604 N