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3 years ago

What mass of NH3 can be made from 35.0 grams of N2

Physics

1 answer:

Allushta [10]3 years ago

4 0

42.5g

Explanation:

Given parameters:

Mass of N₂= 35g

Unknown:

Mass of NH₃ = ?

Solution:

Equation of the reaction:

N₂ + 3H₂ → 2NH₃

To solve this problem, we work from the known species to the unknown. The known here is the reacting mass of the N₂. From this we can find the number of moles of the N₂.

Number of moles of N₂ = $\frac{mass}{molar mass}$

molar mass of N₂ = 28g/mol

Number of moles = $\frac{35}{28}$ = 1.25moles

From the equation of the reaction:

1 mole of N₂ produced 2 moles of NH₃

1.25 moles of N₂ will produce 2 x 1.25 = 2.5moles of NH₃

Mass of NH₃ = Number of moles of NH₃ x molar mass of NH₃

= 2.5 x (14 + 3)

= 42.5g

Learn more:

number of moles brainly.com/question/1841136

#learnwithBrainly

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Read 2 more answers

A small branch is wedged under a 200 kg rock and rests on a smaller object. The smaller object is 2.0 m from the large rock and

Alexxandr [17]

Answer:

$F =326.7 \ N$

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Explanation:

From the question we are told that

The mass of the rock is $m_r = 200 \ kg$

The length of the small object from the rock is $d = 2 \ m$

The length of the small object from the branch $l = 12 \ m$

An image representing this lever set-up is shown on the first uploaded image

Here the small object acts as a fulcrum

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Here $\theta$ is very small so $cos\theta * l = l$

and $cos\theta * d = d$

Hence

$F * l - W * d = 0$

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substituting values

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3 years ago

What must be the acceleration of a train in order for it to stop 12 m/s in a distance if 541 m

earnstyle [38]

Answer:

The acceleration of the train must be - 0.133 m/s²

Explanation:

Lets explain how to solve the problem

A train in order for it to stop 12 m/s in a distance if 541 m

That means the initial velocity of the train is 12 m/s

Its final velocity is zero (stop)

The distance it covers is 541 m

We want to find its acceleration

The acceleration will be negative quantity because the train reduced its

velocity from 12 m/s to zero

We need rule contains velocity, acceleration and distance

So we will use ⇒ v² = u² + 2as, where v is the final velocity, u is the

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agasfer [191]

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