What mass of NH3 can be made from 35.0 grams of N2
1 answer:
42.5g
Explanation:
Given parameters:
Mass of N₂= 35g
Unknown:
Mass of NH₃ = ?
Solution:
Equation of the reaction:
N₂ + 3H₂ → 2NH₃
To solve this problem, we work from the known species to the unknown. The known here is the reacting mass of the N₂. From this we can find the number of moles of the N₂.
Number of moles of N₂ =
molar mass of N₂ = 28g/mol
Number of moles = = 1.25moles
From the equation of the reaction:
1 mole of N₂ produced 2 moles of NH₃
1.25 moles of N₂ will produce 2 x 1.25 = 2.5moles of NH₃
Mass of NH₃ = Number of moles of NH₃ x molar mass of NH₃
= 2.5 x (14 + 3)
= 42.5g
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a) see attached, a = g sin θ
b)
c) v = √(2gL (1-cos θ))
Explanation:
In the attached we can see the forces on the sphere, which are the attention of the bar that is perpendicular to the movement and the weight of the sphere that is vertical at all times. To solve this problem, a reference system is created with one axis parallel to the bar and the other perpendicular to the rod, the weight of decomposing in this reference system and the linear acceleration is given by
Wₓ = m a
W sin θ = m a
a = g sin θ
b) The diagram is the same, the only thing that changes is the angle that is less
θ' = 9/2 θ
c) At this point the weight and the force of the bar are in the same line of action, so that at linear acceleration it is zero, even when the pendulum has velocity v, so it follows its path.
The easiest way to find linear speed is to use conservation of energy
Highest point
Em₀ = mg h = mg L (1-cos tea)
Lowest point
Emf = K = ½ m v²
Em₀ = Emf
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v = √(2gL (1-cos θ))
