What mass of NH3 can be made from 35.0 grams of N2

Physics

1 answer:

Allushta [10]3 years ago

4 0

42.5g

Explanation:

Given parameters:

Mass of N₂= 35g

Unknown:

Mass of NH₃ = ?

Solution:

Equation of the reaction:

N₂ + 3H₂ → 2NH₃

To solve this problem, we work from the known species to the unknown. The known here is the reacting mass of the N₂. From this we can find the number of moles of the N₂.

Number of moles of N₂ = $\frac{mass}{molar mass}$

molar mass of N₂ = 28g/mol

Number of moles = $\frac{35}{28}$ = 1.25moles

From the equation of the reaction:

1 mole of N₂ produced 2 moles of NH₃

1.25 moles of N₂ will produce 2 x 1.25 = 2.5moles of NH₃

Mass of NH₃ = Number of moles of NH₃ x molar mass of NH₃

= 2.5 x (14 + 3)

= 42.5g

Learn more:

number of moles brainly.com/question/1841136

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Water flows through a 4.50-cm inside diameter pipe with a speed of 12.5 m/s. At a later position, the pipe has a 6.25-cm inside

jek_recluse [69]

Given,

The initial inside diameter of the pipe, d₁=4.50 cm=0.045 m

The initial speed of the water, v₁=12.5 m/s

The diameter of the pipe at a later position, d₂=6.25 cm=0.065 m

From the continuity equation,

$\begin{gathered} A_1v_1=A_2v_2 \\ \pi(\frac{d_1}{2})^2v_1=\pi(\frac{d_2}{2})^2v_2 \\ \Rightarrow d^2_1v_1=d^2_2v_2 \end{gathered}$

Where A₁ is the area of the cross-section at the initial position, A₂ is the area of the cross-section of the pipe at a later position, and v₂ is the flow rate of the water at the later position.

On substituting the known values,