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svetoff [14.1K]
3 years ago
14

Mass is constant, but weight can change with location. Explain.

Physics
1 answer:
xxMikexx [17]3 years ago
4 0
Weight is relative to gravity. You weigh more on a planet or area that has more gravity because it is pulling you down more. Mass is a measure of how much matter there is but weight is the measure of the pull of gravity on an object
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What are organelles?<br>Which part of a cell holds organelles?​
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An organelle is a structure in a cell that has specific jobs to do. Organelles are held in the cytoplasm

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On the Apollo 14 mission to the moon, astronaut Alan Shepard hit a golf ball with a golf club improvised from a tool. The free-f
aliya0001 [1]

Answer:

15.3 s and 332 m

Explanation:

With the launch of projectiles expressions we can solve this problem, with the acceleration of the moon

    gm = 1/6 ge

    gm = 1/6  9.8 m/s² = 1.63 m/s²

We calculate the range

    R = Vo² sin 2θ  / g

    R = 25² sin (2 30) / 1.63

    R= 332 m

We will calculate the time of flight,

   Y = Voy t – ½ g t2  

   Voy = Vo sin θ

When the ball reaches the end point has the same initial  height Y=0

0 = Vo sin  t – ½  g t2

0 = 25 sin (30)  t – ½ 1.63 t2

0= 12.5 t –  0.815 t2

We solve the equation

0= t ( 12.5 -0.815 t)

 t=0 s

t= 15.3 s

The value of zero corresponds to the departure point and the flight time is 15.3 s

Let's calculate the reach on earth

R2 = 25² sin (2 30) / 9.8

R2 = 55.2 m

R/R2 = 332/55.2

R/R2 = 6

Therefore the ball travels a distance six times greater on the moon than on Earth

5 0
3 years ago
Please help solving this physics question
sp2606 [1]
True
False
False.
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4 0
3 years ago
The center of gravity of an ax is on the centerline of the handle, close to the head. Assume you saw across the handle through t
andrew-mc [135]

Answer:

I believe it is they will weigh the same

Explanation:

Center of gravity is the axis on which the mass rotates evenly if I remember correctly from AP Physics

3 0
3 years ago
Helium–neon laser light (λ = 632.8 nm) is sent through a 0.350-mm-wide single slit. What is the width of the central maximum on
Cloud [144]

Answer:

The width of the central bright fringe is 7.24 mm.

Explanation:

Given that,

Wavelength = 632.8 nm

Width d= 0.350 mm

Distance between screen and slit D= 2.00 m

We need to calculate the distance

Using formula of distance

y_{m}=\dfrac{\lambda D}{d}

Put the value into the formula

y_{m}=\dfrac{632.8\times10^{-9}\times2.00}{0.350\times10^{-3}}

y_{m}=3.62\ mm

We need to calculate the width of the central bright fringe

Using formula of width

width = 2\times|y_{m}|

Put the value into the formula

width=2\times3.62

width = 7.24\ mm

Hence, The width of the central bright fringe is 7.24 mm.

5 0
3 years ago
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