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3 years ago

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If a copper acetate hydrate, Cux(C2H3O2)yzH20 compound is found to contain 31.82% copper, 59.14% acetate, and the remainder is w

ater. What is the empirical formula?

1 answer:

Aloiza [94]3 years ago

4 0

The Subscripts are 1, 1, 2 Cu(C2H3O2) 2H2O PLZ mark brainleist

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What is the approximate percent by mass of potassium in KHCO3?

lozanna [386]

Answer:

The mass percent of potassium is 39%

Option C is correct

Explanation:

Step 1: Data given

Atomic mass of K = 39.10 g/mol

Atomic mass of H = 1.01 g/mol

Atomic mass of C = 12.01 g/mol

Atomic mass of O = 16.0 g/mol

Step 2: Calculate molar mass of KHCO3

Molar mass KHCO3 = 39.10 + 12.01 + 1.01 + 3*16.0

Molar mass KHCO3 = 100.12 g/mol

Step 3: Calculate mass percent of potassium (K)

%K = (atomic mass of K / molar mass of KHCO3) * 100%

%K = (39.10 / 100.12) * 100%

%K = 39.05 %

The mass percent of potassium is 39%

Option C is correct

8 0

3 years ago

23. The reaction

Sindrei [870]

Answer:

b mi disputa se eu não asetar

6 0

3 years ago

2. Matt went to his friend’s party. He ate a big meal and drank a keg of beer. He felt heartburn after the meal and took Tums to

evablogger [386]

Answer:

390.85mL

Explanation:

Step 1:

Data obtained from the question.

Initial pressure (P1) = 780 torr

Initial volume (V1) = 400mL

Initial temperature (T1) = 40°C = 40°C + 273 = 313K

Final temperature (T2) = 25°C = 25°C + 273 = 298K

Final pressure (P2) = 1 atm = 760torr

Final volume (V2) =?

Step 2:

Determination of the final volume i.e the volume of the gas outside Matt's body.

The volume of the gas outside Matt's body can be obtained by using the general gas equation as shown below:

P1V1/T1 = P2V2/T2

780 x 400/313 = 760 x V2 /298

Cross multiply to express in linear form

313 x 760 x V2 = 780 x 400 x 298

Divide both side by 313 x 760

V2 = (780 x 400 x 298) /(313 x 760)

V2 = 390.85mL

Therefore, the volume of the gas outside Matt's body is 390.85mL

3 0

3 years ago

What is the mass of 3.20x10^23 formula units of iron (III) oxide (Fe2O3)?

yaroslaw [1]

The mass of iron (III) oxide (Fe2O3) : 85.12 g

<h3>Further explanation</h3>

Given

3.20x10²³ formula units

Required

The mass

Solution

1 mole = 6.02.10²³ particles

Can be formulated :

N = n x No

N = number of particles

n = mol

No = 6.02.10²³ = Avogadro's number

mol of Fe₂O₃ :

$\tt n=\dfrac{3.2.10^{23}}{6.02.10^{23}}=0.532$

mass of Fe₂O₃ (MW=160 g/mol)

$\tt mass=mol\times MW=0.532\times 160=85.12~g$

4 0

3 years ago

You can choose from four different materials to make the handrails that run up the stairs and around the playhouse: steel, alumi

Oduvanchick [21]

I think it would be minimize so u can have more friction

8 0

3 years ago