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sdas [7]
3 years ago
13

If a copper acetate hydrate, Cux(C2H3O2)yzH20 compound is found to contain 31.82% copper, 59.14% acetate, and the remainder is w

ater. What is the empirical formula?
Chemistry
1 answer:
Aloiza [94]3 years ago
4 0
The Subscripts are 1, 1, 2 Cu(C2H3O2) 2H2O PLZ mark brainleist
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Which of the following atoms will not react with water? A. K B. Li C. Pb D. Na
Montano1993 [528]
The answer would be C. Pb
3 0
3 years ago
Question 1 of 10
Zepler [3.9K]
A. The pH indicates how acidic or basic a
solution is.
8 0
3 years ago
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A una mezcla de 300g, formada con 60% P/P de Hierro y 40% P/P de Arena, se le adicionan 135g de Cobre y 2,77g de Aluminio. ¿Cuál
Svetllana [295]

Answer:

\%P/P_{hierro}=41.1\%\\\\\%P/P_{arena}=24.4\%\\\\\%P/P_{cobre}=30.8\%\\\\\%P/P_{aluminio}=0.6\%

Explanation:

¡Hola!

En este caso, dado que estamos tratando con problem sobre porcentaje peso/peso de hierro, arena, cobre y aluminio, primero debemos calcular la masa inicial de estos dos primeros en la mezcla original de acuerdo con:

m_{hierro}=300g*0.60=180g\\\\m_{arena}=300*0.40=120g

Ahora si podemos calcular la masa de la mezcla final como la suma de las masas de todos los constituyentes de la mezcla:

m_T=180g+120g+135g+2.77g=437.77g

Finalmente, podemos calcular los porcentajes P/P como se muestra a continuación:

\%P/P_{hierro}=\frac{180g}{437.77g} *100\%=41.1\%\\\\\%P/P_{arena}=\frac{120g}{437.77g} *100\%=24.4\%\\\\\%P/P_{cobre}=\frac{135g}{437.77g} *100\%=30.8\%\\\\\%P/P_{aluminio}=\frac{g}{437.77g} *100\%=0.6\%

¡Saludos!

5 0
3 years ago
The following is a list of weak acids and their Ka values.HOCl hypochlorous acid 3.5 x 10^-8H2S hydrogen sulfide 1.1 x 10^-7HCN
notsponge [240]

Answer:

(a) HNO₂ nitrous acid 4.5 x 10^-4 is strong acid

(b) Ka expression Ka = \frac{[H^{+}][NO_{2}  ^{-}] }{[HNO_{2}] }

(c) List of Conjugate Bases

OCl⁻, S²⁻, CN⁻, NO₂⁻

(d) cyanide ion is strongest conjugate base.

(e) pH and pOH of Hypochlorous acid = 4.22 & 9.77

     pH and pOH of hydrogen sulfide = 4 & 10

    pH and pOH of  hydrocyanic acid = 5.2 & 8.79

    pH and pOH of  nitrous acid = 2.17 & 11.8

Explanation:

(a) Ka and acidity are directly proportional to each other

hence nitrous acid is the strongest acid since it has highest Ka value.

(b) Ka expression of nitrous acid  

                              HNO₂ → H⁺ + NO₂⁻

                     ⇒       Ka = \frac{[H^{+}][NO_{2}  ^{-}] }{[HNO_{2}] }

(c) Conjuagte base for HOCl hypochlorous acid = OCl⁻(hypochlorite ion)

                                 H₂S hydrogen sulfide = S²⁻(sulphide ion)

                                 HCN hydrocyanic acid = CN⁻(cyanide ion)

                                 HNO₂ nitrous acid = NO₂⁻(nitrite ion)

<u>(d) We know according to Bronsted acid base  concept Weak acid have strongest conjugate base</u>

according to this hydrocyanic acid is weak acid so the corresponding conjugate base i.e. cyanide ion is strongest conjugate base.

5 0
3 years ago
Part A: Calculate the mass of butane needed to produce 75.6g of carbon dioxide.
lisabon 2012 [21]

Answer:

Multiply the number of moles of butane by its molar mass, 58.12g/mol, to produce the mass of butane. Mass of butane = 18.8g.

Explanation:

Part B:

The mass of water produced when 4.86 g of butane(C4H10) react with excess oxygen is calculated as below

calculate the moles of C4H10 used = mass/molar mass

moles = 4.86g/58 g/mol =0.0838 moles

write a balanced equation for reaction

2 C4H10 + 13 O2 = 8 CO2 + 10 H2O

by use of mole ratio between C4H10 to H2O which is 2:10 the moles of

H20= 0.0838 x10/2 = 0.419 moles of H2O

mass = moles x molar mass

=0.419 molx 18 g/mol = 7.542 grams of water is formed

5 0
3 years ago
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