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kvv77 [185]
2 years ago
10

Which functional group is found in an amine?

Chemistry
2 answers:
kirill [66]2 years ago
8 0

Answer:

N is single bonded to R, and single bonded twice to H.

Explanation:

The functional group present in an amine will not be complete without mentioning the nitrogen group present in the compound.

Amines are organic compounds that show appreciable basicity. They are regarded as the derivatives of ammonia where one or two or the three hydrogen atoms has/have been replaced been replaced by alkyl or aryl groups.

  • Amines are classified as primary, secondary or tertiary based on the number of substituted hydrogen atoms they carry.
  • The nitrogen bonded to the R - aryl group and bonded to hydrogen is a good description of the functional group.
natima [27]2 years ago
8 0

Answer:

b

Explanation:

because i said so brudda

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Explanation:

North and South must always be opposite of each other.

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3 years ago
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5 0
3 years ago
Sodium hydroxide reacts with aluminum and water to produce hydrogen gas: 2 Al(s) + 2 NaOH(aq) + 6 H2O(l) → 2 NaAl(OH)4(aq) + 3 H
lianna [129]

Answer:

The mass of hydrogen gas formed is 0.205 grams

Explanation:

<u>Step 1:</u> Data given

Mass of 1.83 grams of Al

Mass of NaOH = 4.30 grams

Molar mass of Al = 26.98 g/mol

Molar mass of NaOH = 40 g/mol

<u>Step 2:</u> The balanced equation:

2 Al(s) + 2 NaOH(aq) + 6 H2O(l) → 2 NaAl(OH)4(aq) + 3 H2(g)

<u>Step 3:</u> Calculate moles of Al

Moles Al = mass Al / Molar mass Al

Moles Al = 1.83 grams / 26.98 g/mol

Moles Al = 0.0678 moles

<u>Step 4:</u> Calculate moles of NaOH

Moles NaOH = 4.30 grams / 40 g/mol

Moles NaOH = 0.1075 moles

<u>Step 5</u>: Calculate limiting reactant

For 2 moles of Al, we need 2 moles of NaOH

Aluminium is the limiting reactant. It will completely be consumed ( 0.0678 moles)

NaOH is in excess. There will react 0.0678 moles

There will remain 0.1075 - 0.0678 = 0.0397 moles

<u>Step 6</u>: Calculate moles of hydrogen

For 2 moles of Al, we need 2 moles of NaOH, to produce 3 moles of hydrogen

For 0.0678 moles of Al, there is produced 0.0678 *3/2 = 0.1017 moles of H2

<u>Step 7</u>: Calculate mass of H2

Mass of H2 = Moles H2 * Molar mass of H2

Mass of H2 = 0.1017 moles * 2.02 g/mol

Mass of H2 = 0.205 grams

The mass of hydrogen gas formed is 0.205 grams

6 0
3 years ago
Water,h2o is an example of
expeople1 [14]
Polair molecule, because the oxygen is slightly more negative than the two hydrogen atoms. Making water slightly negative. Due to the fact oxygen holds the to valence electrons more than the two hydrogen atoms do.
4 0
3 years ago
Read 2 more answers
What volume of a 6.67 m nacl solution contains 3.12 mol nacl??
natima [27]

The volume of a 6.67 m nacl solution that contains 3.12 mol nacl is 0.468.

You just need to follow this formula:

C = n / V

So, it will be

V = n / C

<span>    = 3.12 / 6.67 moles / Liter </span>

<span>     = 0.468 L</span>

6 0
3 years ago
Read 2 more answers
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