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pantera1 [17]
3 years ago
13

Which option is an example of a chemical property

Physics
2 answers:
Juliette [100K]3 years ago
6 0
The answer is flammability
lutik1710 [3]3 years ago
5 0

Answer;

-Flammability

Explanation;

-Chemical properties are characteristics of a material that become evident when the material undergoes a chemical reaction or chemical change. It is a substances ability to change into a whole new substance.

-Examples of Chemical Property include flammability, ability to rot, reactivity, ability to tarnish, ability to rust. Iron, for example, combines with oxygen in the presence of water to form rust.

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What is the kinetic energy of a 150 kg bear running at 3 m/s?
OverLord2011 [107]

Explanation:

KE = ½ mv²

KE = ½ (150 kg) (3 m/s)²

KE = 675 J

5 0
3 years ago
How many balls are there in a ski ball machine?
gtnhenbr [62]

Answer:

i think 2 per each sac

Explanation:

i dont know for sure...

Hope this helps

8 0
3 years ago
The resistance between 2 points in an electrical circuit is 1.1 Ω. What additional resistance
valentinak56 [21]

Answer:

the new resister is 11 ohms.

Explanation:

Set it  up like this.

1/x + 1/1.1 = 1                    Subtract 1/1.1 from both sides

1/x = 1 - 1/1.1

1 - 1/1.1 = 1/11

1/x = 1/11                          Cross multiply

11 = x

If 1/11 bothers you, you could do it it another way.

1 - 1/1.1 = (1.1 - 1 ) / 1.1 = 0.1 / 1.1  Multiply top and bottom by 10

0.1*10/(1.1 * 10 ) = 1 / 11

5 0
3 years ago
A 49.3 g ball of copper has a net charge of 2.0 µc. what fraction of the copper's electrons has been removed? (each copper atom
Serggg [28]
First, find how many copper atoms make up the ball: 
 moles of atoms = (49.3 g) / (63.5 g per mol of atoms) = 0.<span>77638</span><span>mol 
</span> # of atoms = (0.77638 mol) (6.02 × 10^23 atoms per mol) = 4.6738*10^23<span> atoms </span>

<span> There is normally one electron for every proton in copper. This means there are normally 29 electrons per atom:
</span> normal # electrons = (4.6738 × 10^23 atoms) (29 electrons per atom) = <span> <span>1.3554</span></span><span>× 10^25 electrons 
</span>
<span> Currently, the charge in the ball is 2.0 µC, which means -2.0 µC worth of electrons have been removed.
</span><span> # removed electrons = (-2.0 µC) / (1.602 × 10^-13 µC per electron) = 1.2484 × 10^13 electrons removed
 
</span><span> # removed electrons / normal # electrons = </span>
<span>(1.2484 × 10^13 electrons removed) / (1.3554 × 10^25 electrons) = 9.21 × 10^-13 </span>

<span> That's 1 / 9.21 × 10^13 </span>
7 0
3 years ago
Sherry and Ellen are talking about the factors that affect light scattering in the atmosphere. Sherry says one factor is the len
Delvig [45]

Sherry who says one factor is the length of the path of sunlight is correct.

<h3>Factors affecting light scattering</h3>

There are two main factors which affects light scattering, and they include the following;

  1. the size of the particles
  2. wavelength of the light

length of the path of sunlight is equivalent to wavelength of the light.

Thus, we can conclude that Sherry who says one factor is the length of the path of sunlight is correct.

Learn more about light scattering here: brainly.com/question/1381101

#SPJ1

3 0
2 years ago
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