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marusya05 [52]
3 years ago
5

The graph in the figure shows the variation of the electric potential V(x) (in arbitrary units) as a function of the position x

(also in arbitrary units). Which of the choices below correctly describes the orientation of the x-component of the electric field along the x-axis?
A. Ex is positive from x = -2 to x = 0, and negative from x = 0 to x = 2.
B. Ex is negative from x = -2 to x = 0, and positive from x = 0 to x = 2.
C. Ex is negative from x = -2 to x = 2.
D. Ex is positive from x = -2 to x = 2.

Physics
1 answer:
dmitriy555 [2]3 years ago
7 0
The best and most correct answer among the choices provided by your question is the second choice or letter b.

Ex is negative from x = -2 to x = 0, and positive from x = 0 to x = 2 <span>correctly describes the orientation of the x-component of the electric field along the x-axis.</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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Mike is cutting the grass using a human-powered lawn mower. He pushes the mower with a force of 45 n directed at an angle of 41Â
Andrej [43]

Answer:

work done will be equal to 305.05 J

Explanation:

We have given force exerted F = 45 N

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So work done W=45\times cos41^{\circ}\times 9.1=309.05J

So work done will be equal to 305.05 J

7 0
3 years ago
A car travels 100 m while decelerating to 8 m/s in 5 s.<br> a) What was its initial speed?
viktelen [127]

Answer:

Vi = 32 [m/s]

Explanation:

In order to solve this problem we must use the following the two following kinematics equations.

v_{f} =v_{i} - (a*t)\\

The negative sign of the second term of the equation means that the velocity decreases, as indicated in the problem.

where:

Vf = final velocity = 8[m/s]

Vi = initial velocity [m/s]

a = acceleration = [m/s^2]

t = time = 5 [s]

Now replacing:

8 = Vi - 5*a

Vi = (8 + 5*a)

As we can see we have two unknowns the initial velocity and the acceleration, so we must use a second kinematics equation.

v_{f}^{2} = v_{i}^{2} - (2*a*d)

where:

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(8^2) = (8 + 5*a)^2 - (2*a*100)

64 = (64 + 80*a + 25*a^2) - 200*a

0 = 80*a - 200*a + 25*a^2

0 = - 120*a + 25*a^2

0 = 25*a(a - 4.8)

therefore:

a = 0 or a = 4.8 [m/s^2]

We choose the value of 4.8 as the acceleration value, since the zero value would not apply.

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what is the force per meter on a straight wire carrying 5.0 a when it is placed in a magnetic field of 0.020 t
Dvinal [7]

The Force per meter on a straight wire carrying current in a magnetic field is<u>  0.045 N/m.</u>

<u>Calculation:-</u>

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Substituting the values

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Learn more about force here:-brainly.com/question/12970081

#SPJ4

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astra-53 [7]

The Answer To This Question Is B

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