The graph in the figure shows the variation of the electric potential V(x) (in arbitrary units) as a function of the position x
(also in arbitrary units). Which of the choices below correctly describes the orientation of the x-component of the electric field along the x-axis?
A. Ex is positive from x = -2 to x = 0, and negative from x = 0 to x = 2.
B. Ex is negative from x = -2 to x = 0, and positive from x = 0 to x = 2.
C. Ex is negative from x = -2 to x = 2.
D. Ex is positive from x = -2 to x = 2.
A. Ex is positive from x = -2 to x = 0, and negative from x = 0 to x = 2.
B. Ex is negative from x = -2 to x = 0, and positive from x = 0 to x = 2.
C. Ex is negative from x = -2 to x = 2.
D. Ex is positive from x = -2 to x = 2.
1 answer:
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Refer to the diagram shown below.
W₁ = (4 kg)*(9.8 m/s²) = 39.2 N
W₂ = (1 kg)*(9.8 m/s²) = 9.8 N
The normal reaction on the 4-kg mass is
N = (39.2 N)*cos(25°) = 35.5273 N
The force acting down the inclined plane due to the weight is
F = (39.2 N)*sin(25°) = 16.5666 N
The net force that accelerates the 4-kg mass at a m/²s down the plane is
F - W₂ = (4 kg)*(a m/s²)
4a = 16.5666 - 9.8
a = 1.6917 m/s²
Answer: 1.69 m/s² (nearest hundredth)
W₁ = (4 kg)*(9.8 m/s²) = 39.2 N
W₂ = (1 kg)*(9.8 m/s²) = 9.8 N
The normal reaction on the 4-kg mass is
N = (39.2 N)*cos(25°) = 35.5273 N
The force acting down the inclined plane due to the weight is
F = (39.2 N)*sin(25°) = 16.5666 N
The net force that accelerates the 4-kg mass at a m/²s down the plane is
F - W₂ = (4 kg)*(a m/s²)
4a = 16.5666 - 9.8
a = 1.6917 m/s²
Answer: 1.69 m/s² (nearest hundredth)